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kaheart [24]
3 years ago
15

PLS HELP ASAP!!!! I WILL GIVE BRAINLIEST!!!!!!!!!!

Mathematics
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

i dk but i will try

C

Step-by-step explanation:

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Statistically, numbers account for nearly half of all fatal collisions when the major factor is
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C) alcohol because drunk driving
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Jack bought a shirt for $14 because it was discounted 30%. what is the regular price?
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All you have to do is 14*.30 which equals to $4.20


8 0
3 years ago
The sum of three consecutive even numbers is 96. What is the smallest of the three numbers
lidiya [134]
The answer is 30.

First off, the numbers are consecutive even numbers. So, the difference between every consecutive number is 2 (numbers go from even to odd to even to odd...). Since the sum of their numbers is 96, I divided that by 3 to get 32. This gives me the median of the three numbers. To find the smallest number, I simply subtracted 2 from the 32.


This may help:

96/3=32

32 + 32 + 32 = 96
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3 years ago
I need some help with geometry.
motikmotik

Answer:

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Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A researcher decides to split scores on an exam into quartiles. She determines that a score of 64 is at the 25th percentile, a s
allochka39001 [22]

Answer:

Answer : A

Step-by-step explanation:

The given data is 25 th percentile is 64, 50th percentile is 74 and 75 th percentile is 80.

percentage : 25    50   75

  score        : 64    74    80

Median:- The median is obtained by first arranging the data in ascending or descending order and applying the following rule.

If the number of observations is odd, then the median is  observation

(\frac{n+1}{2}) ^{th} term

If the number of observations is even, then the median is  observation and  observations.

(\frac{n}{2}+1) ^{th}

given n=3, middle term is '74'

 In this given data the median is (M) = 74

Interquartile range IQR = median of upper half-median of lower half

                                       = 80-64

                                       = 16

                            IQR = 16

8 0
3 years ago
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