a regular polygon has all equal sides.
a PENTA=5, pentagon has 5 sides, so a regular pentagon has 5 equal sides.
![\bf \textit{area of a polygon}\\\\ A=\cfrac{1}{2}ap~~ \begin{cases} a=apothem\\ p=perimeter\\[-0.5em] \hrulefill\\ a=K\\ p=\stackrel{3+3+3+3+3}{15} \end{cases}\implies A=\cfrac{1}{2}K15\implies A=\cfrac{15}{2}K](https://tex.z-dn.net/?f=%20%5Cbf%20%5Ctextit%7Barea%20of%20a%20polygon%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dap~~%20%5Cbegin%7Bcases%7D%20a%3Dapothem%5C%5C%20p%3Dperimeter%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20a%3DK%5C%5C%20p%3D%5Cstackrel%7B3%2B3%2B3%2B3%2B3%7D%7B15%7D%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7DK15%5Cimplies%20A%3D%5Ccfrac%7B15%7D%7B2%7DK%20)
Answer:
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Answer:
B. 8 ft
Step-by-step explanation:
The area of the rectangle is ...
A = LW = (16 ft)(4 ft) = 64 ft²
The area of the square in terms of its side length is ...
A = s²
For the square to have the area of the rectangle, its side length must be ...
64 ft² = s²
s = √(64 ft²) = 8 ft
A side of the square is 8 feet long.
Your answer would be 12x + 8 because there are 4 sides to a square and they are all 3x + 2, so you would need to multiply 3x + 2 by 4 which you can do by expanding brackets which gives you 4(3x + 2) and thus when you multiply it out you get 12x + 8. I hope this helps!
