All categories

2 years ago

I just need help typing it out

Mathematics

1 answer:

Lena [83]2 years ago

7 0

Ok so basically what u need to do is

You might be interested in

Please help..........................

Kobotan [32]

The rate of change is
(2- (-1))/ (3/2-(-4)) => 3 / (11/2)
that is equal to 6/11 so almost 1/2

5 0

3 years ago

What is the answer to this question–1 × –5?

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

a minus times by another minus makes a positive, so it is basically 1 x 5

8 0

3 years ago

Read 2 more answers

Please help me solve this

grigory [225]

Answer:

The length of river D is 2550

length of river C is 2550+500=3050

Step-by-step explanation:

Let the river D be 'x'

and the river C is (x+500)

x + x + 500 = 5600

2x + 500 = 5600

2x = 5600 - 500

2x = 5100

x = 5100/2

x = 2550

The length of river D is 2550

length of river C is 2550+500=3050

7 0

2 years ago

What is the difference from c(2,-1) to d(5,3) a.5 units b.25 units c. 1 unit d.

Naddika [18.5K]

<h3>Answer: A) 5 units</h3>

====================================================

Explanation:

The two points given are

C = (x1,y1) = (2,-1)

D = (x2,y2) = (5,3)

Use the distance formula

$d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(2-5)^2 + (-1-3)^2}\\\\d = \sqrt{(-3)^2 + (-4)^2}\\\\d = \sqrt{9 + 16}\\\\d = \sqrt{25}\\\\d = 5\\\\$

The distance from C to D is 5 units. This is the same as saying segment CD is 5 units long.

6 0

2 years ago

The x-y is the answer can someone please explain to me how to do

guapka [62]

Answer:

Step-by-step explanation:

$\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y})-(\sqrt{x-y})*(\sqrt{x+y}-\sqrt{x-y})}{(\sqrt{x+y}-\sqrt{x-y})*(\sqrt{x+y}+\sqrt{x-y})}\\\\=\frac{\sqrt{x-y}*(\sqrt{x+y}+\sqrt{x-y}-\sqrt{x+y}+\sqrt{x-y})}{(\sqrt{x+y})^2-(\sqrt{x-y)^{2}}}\\\\=\frac{\sqrt{x-y}*2\sqrt{x-y}}{x+y-x+y}\\\\=2*\frac{x-y}{2y}=\frac{x-y}{y}\\\\(\frac{\sqrt{x-y}}{\sqrt{x+y}-\sqrt{x-y}}-\frac{\sqrt{x-y}}{\sqrt{x+y}+\sqrt{x-y}})*y=\frac{x-y}{y}*y\\\\=x-y$

4 0

3 years ago

Read 2 more answers