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WINSTONCH [101]
2 years ago
14

I just need help typing it out

Mathematics
1 answer:
Lena [83]2 years ago
7 0
Ok so basically what u need to do is
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4x − 4<br> 10x − 20<br> ×<br> 15x + 15<br> 3x − 3<br> ×<br> 6x − 12<br> 20x + 20.
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what is the question dudd

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Rodrick and Valentina drove to the coast. Rodrick drove 38 9−− 10miles. Then Valentina drove the last 51 3− 5miles. How far did
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What is the slope of your line perpendicular to y=5x-12
krok68 [10]

The slope of your line is the x-coefficient: 5.

The slope of a perpendicular line is the negative reciprocal of that: -1/5.

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Solve for x. 2/x-3=x/12-4x
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x=  47 18+2  201  i  ≈0.382978723+0.603295612i x=  47 −2  201  i+18  ≈0.382978723−0.603295612i  Hopefully this makes just the same amount of sense as this question

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2 years ago
A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so
mamaluj [8]

Answer:

1) Is the pattern an arithmetic sequence?​

Yes it is

2)Identify a and d.​

a = First term = 2

d = Common difference = 2

3) Write the 50th term of the sequence.​

50th term = 100

4) Find the total number of logs in the first 10 rows.​

= 1010 logs

Step-by-step explanation:

Is the pattern an arithmetic sequence?​

Yes it is

2) Identify a and d.​

A pyramid of logs has 2 logs in the top row, 4 logs in the second row from the top, 6 logs in the third row from the top, and so on,

The formula for arithmetic sequence =

an = a+ (n - 1)d

a = First term

d = Common difference

For the above question:

a = 2

d = Second term - First term

= 4 - 2

d = 2

3) Write the 50th term of the sequence.​

Using the formula for arithmetic sequence

an = a+ (n - 1)d

a = 2

n = 50

d = 2

a50 = 2 + (50 - 1)2

= 2 + (49)2

= 2 + 98

= 100

The 50th term = 100

4)Find the total number of logs in the first 10 rows.​

Sum of first n terms = n/2(a + l)

n = 10

a = first term = 2

We are told that there are 200 logs in the bottom row, hence:

l = last term = 200 logs

Hence,

Sn = 10/2×[ (2 + 200

= 5(202)

= 1010 logs

7 0
3 years ago
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