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Aleonysh [2.5K]
3 years ago
6

What is the area of the blue glass will be needed to fill each butterfly dot if the distance around each dot it 24pie inches

Mathematics
2 answers:
Amanda [17]3 years ago
8 0

Answer:b

Step-by-step explanation:

this is easy

geniusboy [140]3 years ago
3 0

Answer:

bgvbhjnmnh bfvc

Step-by-step explanation:

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Please help solve the inequality.
gulaghasi [49]

Answer:

Are there two you're asking for?

#2: x ≥ 9

#3: x > -2

Step-by-step explanation:

#2 Work:

x - 13 ≥ -4

Step 1: Add 13 to both sides

x - 13 + 13 ≥ -4 + 13

Add -4 and 13 to get 9.

x ≥ 9

#3 Work:

x/2 > -1

Multiply both sides by 2. Since 2 is positive, the inequality direction remains the same

x/2 * 2 > -1 * 2

x > -2

5 0
2 years ago
2root 3 x 3 root 8 fully simplified
LuckyWell [14K]

Answer:

  • 12\sqrt{6}

Step-by-step explanation:

<h3>Given expression</h3>

  • 2 \sqrt{3} *3\sqrt{8}

<h3>Simplify the expression in steps as below</h3>

  • 2 \sqrt{3} *3\sqrt{8}  =
  • 2 \sqrt{3} *3\sqrt{2^2*2} =
  • 2 \sqrt{3} *3*2\sqrt{2} =
  • 2*6* \sqrt{3} *\sqrt{2} =
  • 12* \sqrt{3*2}  =
  • 12\sqrt{6}

Used properties in solution process:

  • \sqrt{a^2} =a
  • \sqrt{a}\sqrt{b}  =\sqrt{ab}
8 0
2 years ago
Which of the following statement is false?
Setler79 [48]

Answer:

c not all complex are imaginary

but all imaginary are complex

please brainlist

7 0
3 years ago
Read 2 more answers
How many solutions does this graph have?<br> 1<br> 3<br> 2<br> 0
vagabundo [1.1K]

Answer:

3

Step-by-step explanation:

i think

6 0
3 years ago
Find an n^th degree polynomial with real coefficients satisfying the given conditions. n = 3; -2 and 2 i are zeros; f(-1) = 15.
Ira Lisetskai [31]
So, n = 3, is a 3rd degree polynomial, roots are -2 and 2i

well 2i is a complex root, or imaginary, and complex root never come all by their lonesome, their sister is always with them, the conjugate, so if 0+2i is there, 0-2i is there too

so, the roots are -2, 2i, -2i

now... \bf \begin{cases}&#10;x=-2\implies x+2=0\implies &(x+2)=0\\&#10;x=2i\implies x-2i=0\implies &(x-2i)=0\\&#10;x=-2i\implies x+2i=0\implies &(x+2i)=0&#10;\end{cases}&#10;\\\\\\&#10;(x+2)\underline{(x-2i)(x+2i)}=0\\\\&#10;-----------------------------\\\\&#10;\textit{difference of squares}&#10;\\ \quad \\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)\\\\&#10;-----------------------------\\\\&#10;(x+2)[x^2-(2i)^2]=0\implies (x+2)[x^2-(2^2i^2)]=0&#10;\\\\\\&#10;(x+2)[x^2-(4\cdot -1)]=0\implies (x+2)(x^2+4)=0&#10;\\\\\\&#10;x^3+2x^2+4x+8=0

now, if we check f(-1), we end up with 5, not 15
hmmm

so, how to turn our 5 to 15? well, 3*5, thus

\bf 3(x^3+2x^2+4x+8)=f(x)\implies 3(5)=f(-1)\implies 15=f(-1)

usually, when we get the roots, or zeros, if any common factor that is a constant is about, they get in a division with 0 and get tossed, and aren't part of the roots, thus, we can simply add one, in this case, the common factor of 3, to make the 5 turn to 15
6 0
3 years ago
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