Can someone please help me and explain

Today joelle walked at a rate of 3 miles per hour and she ran 15 minutes at a rate of 6 miles per hour.How many total miles did

svetoff [14.1K]

I added a screenshot with the complete question

Answer:
Total miles = 2.5 miles

Explanation:
1- While walking:
We are given that Joelle walked 20 minutes at a rate of 3 miles per hour.
This means that she walked $\frac{20}{60} = \frac{1}{3}$ of an hour at a rate of 3 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
Substitute with the givens to get the distance she covered while walking:
Distance = 3 * $\frac{1}{3}$ = 1 mile

2- While running:
We are given that Joelle ran 15 minutes at a rate of 6 miles per hour
This means that she ran $\frac{15}{60} = \frac{1}{4}$ of an hour at a rate of 6 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
Substitute with the givens to get the distance she covered while running:
Distance = 6 * $\frac{1}{4}$ = 1.5 miles

3- getting the total mileage:
Total distance she covered = distance while walking + distance while running
Total distance she covered = 1 + 1.5
Total distance she covered = 2.5 miles

Hope this helps :)

4 0

3 years ago

Find -3(6m-8)+(-4+2m).

mamaluj [8]

Answer: − 16 m + 20

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Surface area, pls help

erastovalidia [21]

192
Solution
(2ft)x(12ft)x(8ft)
Answer
192
Sana po makatulong

5 0

2 years ago

NarStor, a computer disk drive manufacturer, claims that the median time until failure for their hard drives is more than 14,400

Ne4ueva [31]

Answer:

The test statistics is $t = -1.727$

Step-by-step explanation:

From the question we are told that

The data given is

330 620 1870 2410 4620 6396 7822 81028309 12882 14419 16092 18384 20916 23812 25814

The population mean is $\mu = 14400$

The sample size is n = 16

The null hypothesis is $\mu \le 14400$

The alternative hypothesis is $H_a : \mu > 14400$

The sample mean is mathematically evaluated as

$\= x = \frac{\sum x_i}{n}$

So

$\= x = \frac{330+ 620+ 1870 +2410+ 4620+ 6396+ 7822+ 8102+8309+ 12882+ 14419+ 16092+ 18384 +20916+ 23812+ 25814 }{16}$

=> $\= x = 10799.9$

The standard deviation is mathematically represented as

$\sigma =\sqrt{\frac{ \sum (x_i - \=x)^2}{n}}$

So

$\sigma =\sqrt{\frac{(330- 10799.9)^2 + (620- 10799.9)^2+ (1870- 10799.9)^2 +(2410- 10799.9)^2 + (4620- 10799.9)^2 +(6396- 10799.9)^2 +(7822- 10799.9)^2 }{16}} \ ..$

$..\sqrt{ \frac{(8102 - 10799.9)^2 +(8309 - 10799.9)^2 + (12882 - 10799.9)^2 + (14419 - 10799.9)^2 + (16092 - 10799.9)^2 + (18384 - 10799.9)^2 +(20916 - 10799.9)^2 }{16}} \ ...$