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3 years ago

Can someone please help me With BOTH parts of the question ..thanks u

Mathematics

1 answer:

Gala2k [10]3 years ago

3 0

Answer:

-0.89 < -0.51

B. Felipe's Restaurant has less value than Ming's Lodge.

Step-by-step explanation:

If you have a big debt you're going to have less money.

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In a state's pick 3 lottery game, you pay $1.33 to select a sequence of three digits (from 0 to 9), such as 288. if you sel

slega [8]

A. How many different selections are possible?

B. What is the probability of winning?

C. If you win, what is your net profit?

D. Find the expected value

Answer :

A. sequence of three digits (from 0 to 9). so 10 numbers.

We know 3 lottery games. So possible selections = 10^3 = 1000

B. Probability of winning = one outcome / total outcomes

P( winning) = $\frac{1}{1000}$ = 0.001

c. Net profit = winning amount - paid amount

= 384.13 - 1.33 = $382.8

D. expected value

E(x) = net profit * winning probability - paid amount * lost probability

E(x) = 382.8 * 0.001 - 1.33 * 0.999 = -0.95

you expect to lose 95 cents per ticket.

8 0

3 years ago

A parabola has the same vertex as the parabola y = 3(x − 1)^2 + 6 and has a y-intercept of −7. What is the equation of the parab

Semenov [28]

It’s probably B if my math is correct .

8 0

3 years ago

Read 2 more answers

When class 11Y1 found that their favourite teacher, Mr Musson, was leaving they decided to organise a party for him. Lewis, one

TEA [102]

Answer: £14.94

Step-by-step explanation:

36 cartons at £1.56 for 4 = 14.04

2 cartons at £45p = 0.90

6 0

3 years ago

State the vertical asymptote of the rational function. f(x) =((x-9)(x+7))/(x^2-4)

Lubov Fominskaja [6]

$D:x^2-4\not=0\\
D:x^2\not=4\\
D:x\not=-2 \wedge x\not =2\\\\
\displaystyle
\lim_{x\to-2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(-2-9)(-2+7)}{(-2^-)^2-4}=\dfrac{-11\cdot5}{4^+-4}=\dfrac{-55}{0^+}=-55\cdot\infty=-\infty\\
\dfrac{(-2-9)(-2+7)}{(-2^+)^2-4}=\dfrac{-11\cdot5}{4^--4}=\dfrac{-55}{0^-}=-55\cdot(-\infty)=\infty
$

$\displaystyle
\lim_{x\to2^-}\dfrac{(x-9)(x+7)}{x^2-4}=\\
\dfrac{(2-9)(2+7)}{(2^-)^2-4}=\dfrac{-7\cdot9}{4^--4}=\dfrac{-63}{0^-}=-63\cdot(-\infty)=\infty\\
\dfrac{(2-9)(2+7)}{(2^+)^2-4}=\dfrac{-7\cdot9}{4^+-4}=\dfrac{-63}{0^+}=-63\cdot\infty=-\infty\\$

So, the vertical asymptotes are $x=\pm 2$

5 0

4 years ago

Read 2 more answers

Find the sum of 20 + 14 + 8 + ... + (-70)

Tanya [424]

Answer:

-400

Step-by-step explanation:

20 + 14 + 8 + ... + (-70) =

= (-6·1+26)+(-6·2+26)+(-6·3+26)+...+(-6·16+26) =

= -6·(1+2+3+...+16)+26·16 =

= -6·16·17/2+26·16 =

= -6·8·17+26·16 =

= -816+416 =

= -400

5 0

3 years ago