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2 years ago

Can someone please help me With BOTH parts of the question ..thanks u

Mathematics

1 answer:

Gala2k [10]2 years ago

3 0

Answer:

-0.89 < -0.51

B. Felipe's Restaurant has less value than Ming's Lodge.

Step-by-step explanation:

If you have a big debt you're going to have less money.

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Please help!!!!!!!!!!!!!!

GREYUIT [131]

Pay attention here because I'm adding an extra letter to our circle to help keep track of the values in our formula. OUTSIDE of the intercepted arc I'm adding the point E. So the major arc is arc BEG and the minor arc is arc BG. The formula then for us is ∠ $BFG= \frac{1}{2}(arcBEG-arcBG)$ . We just don't have values for the arcs yet. If the measure of the central angle is 4x+238, then the measure of arcBG is also 4x+238. Around the outside of the circle is 360°. So we will use it in an expression. ArcBEG=360-(4x+238). Fitting that into our formula we have $2x+146= \frac{1}{2}[(360-4x-238)-(4x+238)]$ . Doing all the simplifying inside there we have $2x+146= \frac{1}{2}(122-4x-4x-238)$ and $2x+146= \frac{1}{2}(-8x-116)$ . Multiply both sides by 2 to get rid of the fraction: 4x+292=-8x-116. Combine like terms to get 12x = -408 and divide to solve for x. x = -34. Fourth choice down from the top.

3 0

2 years ago

Can someone tell me how many cds in both columns combined be?<br>

Keith_Richards [23]

Answer:

2021= 700cds 2020=750cds

Step-by-step explanation:

Puedes ver como indica en el lado izquierdo que la barra de cds de el 2021 esta en la mitad de 800 y 600 que es igual a 700 cds en 2021

Y en la parte del 2020 se ve que este en la mitad de 800 y 700 considerando el calculo anterior por lo que daría 750 cds en 2020

6 0

9 months ago

Two altitudes of a triangle have lengths $12$ and $14$. What is the longest possible integer length of the third altitude

nataly862011 [7]

The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

a < b+c

2A/12 < 2A/14 + 2A/h

Solve it and get

h<84

b < a+c

2A/14 < 2A/12 + 2A/h

Solve it and get

h > -84

c < a+b

2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

Learn more about TRIANGLE here brainly.com/question/2217700

#SPJ4

8 0

1 year ago

-4x+5 + -13x+39=180 angle measure

mylen [45]

Step-by-step explanation:

−4x+5−13x+39=180

Step 1: Simplify both sides of the equation.

−4x+5−13x+39=180

−4x+5+−13x+39=180

(−4x+−13x)+(5+39)=180(Combine Like Terms)

−17x+44=180

Step 2: Subtract 44 from both sides.

−17x+44−44=180−44

−17x=136

Step 3: Divide both sides by -17.−17x

−17

136

−17

x=−8

Answer:

x=−8

5 0

2 years ago

A performer expects to sell 10,000 tickets for

Lorico [155]

72.1
Brainliest please I’m tryna rank up

5 0

2 years ago