2. Assume the quadrilateral is a square. Then m<4 = 90 m<5 = 45 m<6 = 45
16. Assume it's a regular hexagon. The hexagon can be divided into 6 congruent equilateral triangles. The 3 sides of each equilateral triangle measures 6sqrt(3) m. When you draw a segment from the center of the hexagon to a side of the hexagon, you divide one of the 6 triangles into 2 30-60-90 triangles. The ratio of the lengths of the sides of a 30-60-90 triangle is 1 : sqrt(3) : 2. That segment is also the height of one of the 6 triangles. height = (6sqrt(3))/2 * sqrt(3) = 9 Now we know the base and height of one of the 6 triangles.The area of the hexagon is 6 times the area of one triangle.
area of hexagon = 6 * bh/2 area of hexagon = 6 * 6sqrt(3) m * 9 m/ 2 = 324sqrt(3) /2 m^2 = 162sqrt(3) m^2
