Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
is that a question?
Step-by-step explanation:
Answer:
z = 189/44
Step-by-step explanation:
The "varies jointly" relationship can be expressed by ...
y = kxz
We can find k from the given values.
40 = k(10)(9)
40/90 = k = 4/9 . . . divide by the coefficient of k
Now we want to find z for given values of x and y. That can be found from ...
y = (4/9)xz
9y/(4x) = z . . . . . multiply by 9/(4x)
Filling in the new numbers, we have ...
z = 9·105/(4·55)
z = 4 13/44 = 189/44 ≈ 4.2954...(repeating 54)
Find 
using Pythagorean Theorem,
.
.
.
Hope this helps.
