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gogolik [260]
3 years ago
6

A cereal box says that now it contains 20% more. Originally, it came with 18.5 ounces of cereal. How much cereal does the box co

me with now?
Mathematics
1 answer:
siniylev [52]3 years ago
4 0
The cereal box now contains 22.2 ounces
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I golf club charges $10 to join and
Jobisdone [24]

Answer: He could have played more than 3 games.

Step-by-step explanation:

Hi, to answer this question we have to write an inequality.

I golf club charges $10 to join and $5 per game: So, the cost of playing golf is equal to $10 (joining price) plus the product of the number of games played (x) and the price per game (5).

That expression must be higher than 25, since john paid more than $25.

Mathematically speaking

10+ 5 x > 25

Solving for x

5x >25-10

5x >15

x >15/5

x> 3

He could have played more than 3 games, since his cost was higher ( not equal or higher) than 25.

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3 years ago
There is the picture of the problem i’m really having trouble with it could someone help me plz :)
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6 0
3 years ago
A scale drawing of a building shows 1 inch = 8 feet. How many feet are represented by 3 ¾ inches on the drawing?
Gennadij [26K]

Answer:

30 feet is represented by 3 3/4 inches on the drawing

Step-by-step explanation:

We have the relation as;

1 inch = 8 feet

Thus;

3 3/4 inches = x feet

x = 3 3/4 * 8

x = 15/4 * 8

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6 0
3 years ago
A builder of houses needs to order some supplies that have a waiting time Y for delivery, with a continuous uniform distribution
xenn [34]

Answer:

The Expected cosy of the builder is $433.3

Step-by-step explanation:

$400 is the fixed cost due to delay.

Given Y ~ U(1,4).

Calculating the Variable Cost, V

V = $0 if Y≤ 2

V = 50(Y-2) if Y > 2

This can be summarised to

V = 50 max(0,Y)

Cost = 400 + 50 max(0, Y-2)

Expected Value is then calculated by;

Waiting day =2

Additional day = at least 1

Total = 3

E(max,{0, Y - 2}) = integral of Max {0, y - 2} * ⅓ Lower bound = 1; Upper bound = 4, (4,1)

Reducing the integration to lowest term

E(max,{0, Y - 2}) = integral of (y - 2) * ⅓ dy Lower bound = 2; Upper bound = 4 (4,2)

E(max,{0, Y - 2}) = integral of (y) * ⅓ dy Lower bound = 0; Upper bound = 2 (2,0)

Integrating, we have

y²/6 (2,0)

= (2²-0²)/6

= 4/6 = ⅔

Cost = 400 + 50 max(0, Y-2)

Cost = 400 + 50 * ⅔

Cost = 400 + 33.3

Cost = 433.3

5 0
3 years ago
Read 2 more answers
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