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zysi [14]
3 years ago
6

In 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B. If 70 houses wer

e built in Town A during 210, how many were built in Town B
Mathematics
1 answer:
Stella [2.4K]3 years ago
8 0

Answer:

The number of houses built in Town B is 56.

Step-by-step explanation:

We are given that in 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B.

Also, 70 houses were built in Town A during 210.

Let the number of houses built in Town B be 'x'.

So, according to the question;

Number of houses built in Town A = Number of houses built in Town B + 25% of the houses built in Town B

70 = x + (25\% \times x)

70 = x(1+0.25)

x=\frac{70}{1.25}

x = 56

Hence, the number of houses built in Town B is 56.

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The chamber of commerce of a Florida Gulf Coast community advertises that area residential property is available at a mean cost
Alja [10]

Answer:

a) In the step-by-step explanation.

b)  The null and alternative hypothesis are:

H_0: \mu=125000\\\\H_a:\mu> 125000

c) P-value = 0.015

d) The conclusion, at a level of significance of 0.05, is that there is enough evidence to support the claim that that area residential property is available at a mean cost significantly higher than $125,000 per lot.

e) The claim of the chamber of commerce is false. We have statistical evidence against that claim and we can conclude that the mean prices are significantly higher than $125,000.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim, expressed in the alternative hypothesis, is that area residential property is available at a mean cost significantly higher than $125,000 per lot.

Then, the null and alternative hypothesis are:

H_0: \mu=125000\\\\H_a:\mu> 125000

The significance level is 0.05.

The sample has a size n=32.

The sample mean is M=130000.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12500.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12500}{\sqrt{32}}=2209.71

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{130000-125000}{2209.71}=\dfrac{5000}{2209.71}=2.26

The degrees of freedom for this sample size are:

df=n-1=32-1=31

This test is a right-tailed test, with 31 degrees of freedom and t=2.26, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>2.26)=0.015

As the P-value (0.015) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that that area residential property is available at a mean cost significantly higher than $125,000 per lot.

6 0
3 years ago
There are 10 less trumpet players than saxophone players.The numbers of a saxophone player 3 times the number of trumpet players
Vikentia [17]
There are 5 trumpet players.
if there are 15 saxophone players, there are 10 less trumpet players making it 5.
3 0
3 years ago
38 is what percent of 76?
djyliett [7]
Okay, to find the answer, you would divide the first number by the second number.

   38/76=0.5

To find the decimal as a fraction, move the decimal two spots to the right.

0.5=50%

I hope this helped!
3 0
3 years ago
Ok last question for today <br> Will mark brainliest
Pepsi [2]

Answer:9


Step-by-step explanation:

8 * 9 = 72

8, 16, 24, 32, 40, 48, 56, 64, 72

1, 2, 3, 4, 5, 6, 7, 8, 9

3 0
4 years ago
The average of six numbers is 4. If the of two of those numbers is 2, what is the average of the other four numbers?
matrenka [14]

Answer:

5

Step-by-step explanation:

total sum of the 6 numbers

= 4 ×6

= 24

sum of numbers without the two 2s

= 24 - 2(2)

= 20

average of other 4 numbers

= 20 ÷ 4

= 5

6 0
4 years ago
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