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zysi [14]
2 years ago
6

In 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B. If 70 houses wer

e built in Town A during 210, how many were built in Town B
Mathematics
1 answer:
Stella [2.4K]2 years ago
8 0

Answer:

The number of houses built in Town B is 56.

Step-by-step explanation:

We are given that in 2010, the number of houses built in Town A was 25 percent greater than the number of houses built in Town B.

Also, 70 houses were built in Town A during 210.

Let the number of houses built in Town B be 'x'.

So, according to the question;

Number of houses built in Town A = Number of houses built in Town B + 25% of the houses built in Town B

70 = x + (25\% \times x)

70 = x(1+0.25)

x=\frac{70}{1.25}

x = 56

Hence, the number of houses built in Town B is 56.

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2 years ago
One side of a rectangle is 3 m more than the other. If the perimeter of the rectangle is 30 m, what are its dimensions? *
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Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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A fundraising event offered people a chance to pay $3 to go through a corn maze (shown below) in a field in the fall. The maze e
german

<em>*100% correct answers </em>

Question 1

A fundraising event offered people a chance to pay $3 to go through a corn maze (shown below) in a field in the fall. The maze either led to nothing or a prize of $4 (ie their $3 back and an extra $1). The participants can only move forward and when they come to a fork in the maze they are equally likely to take any one of the paths. What is the expected monetary value for each participant that goes through the maze?  

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3 years ago
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