<img src="https://tex.z-dn.net/?f=x%2B%28-17%29%3D-1%20%3Cbr%3E%0A" id="TexFormula1" title="x+(-17)=-1 &#10;" alt="x+(-17)=-

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Svet_ta [14]

2 years ago

1 
" align="absmiddle" class="latex-formula"> Solve for X

Mathematics

1 answer:

Radda [10]2 years ago

5 0

X+(-17)=-1
x-17=-1
x-17+17=-1+17
x=16

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A circle has the equation 2x2+12x+2y2−16y−150=0.

astra-53 [7]

Answer:

Step-by-step explanation:

hello :

2x²+12x+2y²−16y−150=0

divide by 2 : (x²+6x)+(y²-8y)-75 =0

(x²+6x+9)-9+(y²-8y+16)-16-75 =0

(x+3)²+(y-4)² =10²

The coordinates of the center are (−3,4), and the length of the radius is 10 units.

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2 years ago

A ball is thrown vertically in the air with a velocity of 95 ft/s. The ball is at a height of 120 ft.

sattari [20]

Answer:

The ball is at a height of 120 feet after 1.8 and 4.1 seconds.

Step-by-step explanation:

The statement is incomplete. The complete statement is perhaps the following "A ball is thrown vertically in the air with a velocity of 95 ft/s. What time in seconds is the ball at a height of 120ft. Round to the nearest tenth of a second."

Since the ball is launched upwards, gravity decelerates it up to rest and moves downwards. The position of the ball can be determined as a function of time by using this expression:

$y = y_{o} + v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}$

Where:

$y_{o}$ - Initial height of the ball, measured in feet.

$v_{o}$ - Initial speed of the ball, measured in feet per second.

$g$ - Gravitational constant, equal to $-32.174\,\frac{ft}{s^{2}}$ .

$t$ - Time, measured in seconds.

Given that $y_{o} = 0\,ft$ , $v_{o} = 95\,\frac{ft}{s}$ , $g = -32.174\,\frac{ft}{s^{2}}$ and $y = 120\,ft$ , the following second-order polynomial is found:

$120\,ft = 0\,ft + \left(95\,\frac{ft}{s} \right)\cdot t +\frac{1}{2}\cdot \left(-32.174\,\frac{ft}{s^{2}} \right) \cdot t^{2}$

$-16.087\cdot t^{2} + 95\cdot t -120 =0$

The roots of this polynomial are, respectively:

$t_{1} \approx 4.075\,s$ and $t_{2} \approx 1.831\,s$ .

Both roots solutions are physically reasonable, since $t_{1}$ represents the instant when the ball reaches a height of 120 ft before reaching maximum height, whereas $t_{2}$ represents the instant when the ball the same height after reaching maximum height.

In nutshell, the ball is at a height of 120 feet after 1.8 and 4.1 seconds.

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Pls help me i just need help

Ray Of Light [21]

Step-by-step explanation:

the total cost is, of course, first the cost to buy the copier, and then the running costs per copy made.

it is really that easy.

the equations just put this into mathematical form :

y = 0.02×x + 800

y = 0.06×x + 600

please notice, we put $600 or $800 in as constant term, because these costs are the starting costs that we have, even if we never make a single copy (x = 0).

and then the total cost goes up with every copy we make.

I cannot draw here.

so, to find the number of copies where both copier systems would cost the same, means we have to say both equating deliver the same result :

0.02×x + 800 = 0.06×x + 600

200 = 0.04×x

x = 200 / 0.04 = 5000

when making 5000 copies both costs are the same.

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Ivahew [28]

Answer:

To know what the ratio for the cos of theta, we actually have to see the adjacent and hypotenuse values. cos=adjacent/hypotenuse.

Step-by-step explanation:

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Answer:

I believe the correct answer is D

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