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sveticcg [70]
3 years ago
13

Ana deposits $1,500 in a savings account that earns 4% interest

Mathematics
1 answer:
Masja [62]3 years ago
7 0

Answer:

She will have 1824.98 dollars in five years

Step-by-step explanation:

1500 X 1.04 ^ 5

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You are given the dollar value of a product in 2015 and the rate at which the value of the product is expected to change during
Charra [1.4K]

Answer:

V = $3.50t + $90.5....

Step-by-step explanation:

V(t) is a function of t that expresses the value in year 2000+t.  

We know that the increase is $3.50 times t.

So,

V(t) = $3.50t + c  

where c is the constant.

V(15) =  $3.50 (15) + c = $143     [t=15 as mentioned in the question]

and therefore  

c = $143 - $3.50 (15)

c= $143 - $52.50

c= $90.5  

Now we got the value of c. We can write the equation as  

V = $3.50t + $90.5....

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3 years ago
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Trava [24]

Answer:

A function that is one to one

Step-by-step explanation:

Each input has one output.

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2 years ago
The price of an outdoor grill was marked up 15% over the previous year's model. If the previous year's model sold for $500, what
harkovskaia [24]
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8 0
3 years ago
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Vladimir79 [104]

Answer:

7%

Step-by-step explanation:

8 0
3 years ago
More on Areas. Farmer Jones, and his wife, Dr. Jones, both mathematicians, decide to build a fence in their field to keep the sh
Olin [163]

Answer:

Area covered by the fences will be 16.1 unit²

Step-by-step explanation:

Let the first parabola is represented by the function f(x) = 6x²

and second parabola by g(x) = x² + 9

point of intersection of the graphs will be determined when f(x) = g(x)

6x² = x² + 9

5x² = 9

x² = 1.8

x = ± 1.34

Now we will find the area between these curves drawn on the graph.

Area = \int_{-1.34}^{1.34}[f(x)-g(x)]dx=\int_{-1.34}^{1.34}[6x^{2}-(x^{2}+9)]dx

= \int_{-1.34}^{1.34}(5x^{2}-9)dx

= [\frac{5}{3}x^{3}-9x]_{-1.34}^{1.34}

= [\frac{5}{3}(-1.34)^{3}-9(-1.34)-\frac{5}{3}(1.34)^{3}+9(1.34)]

= [-4.01+12.06-4.01+12.06]

= 16.1 unit²

6 0
3 years ago
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