All categories

3 years ago

What is the standard deviation of the data set given below? 4,7, 8, 9, 12

Mathematics

1 answer:

larisa [96]3 years ago

3 0

Answer:

I think 7

Step-by-step explanation:

4 , 8 , 9 and 12 has factors.

7 has no factor.

4= 2×2

8= 2×4

9= 3×3

12= 3×4

You might be interested in

How to write eight hundred fifty-four and ninety-six hundredths

Anna35 [415]

This good question needs a good answer which is......854.96

7 0

3 years ago

Read 2 more answers

PLEASE HELP! THANKS!

MArishka [77]

Answer:

The question is kinda funny. I think the graph isn't correct cos a and b coordinate ain't right

8 0

2 years ago

Math help guys how wouls i work this out

Andrei [34K]

8 > 7 + $\frac{x}{6}$ Subtract 7 from both sides

1 > $\frac{x}{6}$ Multiply both sides by 6

6 > x Flip it around so it's easier to read

x < 6

You can graph your answer by drawing an open circle at the 6 and coloring the line to the left. The circle should be open, because x is less than 6, not less than or equal to. You would color to the left to show that x can be anything less than 6.

4 0

3 years ago

What is the form of the Difference of Squares identity?

Alecsey [184]

The answer is B

seeing there are 3 way to put it

(a+b)(a-b)=a 2-b 2

(a+b)(a-b)=a^2-b^2

(a+b)(a-b)=a2-b2

and option B matches with the second way to put it i hope this helps

8 0

1 year ago

Find -7a-6B (Picture provided)

sertanlavr [38]

Answer:

Option c

$-7A-6B=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)$

Step-by-step explanation:

First multiply matrix A by -7.

Then multiply the matrix B by -6.

When multiplying a matrix by a number x you must multiply each element of the matrix by x.

Then we perform operation -7A

$-7\left(\begin{array}{ccc}-10&10&8\\-2&-1&5\\-4&8&-6\end{array}\right)=\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)$

Now we perform operation -6B

$-6\left(\begin{array}{ccc}5&6&-4\\10&-6&-10\\-9&1&10\end{array}\right)=\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)$

Now we add the resulting matrices

$\left(\begin{array}{ccc}70&-70&-56\\14&7&-35\\28&-56&42\end{array}\right)+\left(\begin{array}{ccc}-30&-36&24\\-60&36&60\\54&-6&-60\end{array}\right)=\left(\begin{array}{ccc}40&-106&-32\\-46&43&25\\82&-62&-18\end{array}\right)$

7 0

3 years ago