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3 years ago

What is the standard deviation of the data set given below? 4,7, 8, 9, 12

Mathematics

1 answer:

larisa [96]3 years ago

3 0

Answer:

I think 7

Step-by-step explanation:

4 , 8 , 9 and 12 has factors.

7 has no factor.

4= 2×2

8= 2×4

9= 3×3

12= 3×4

You might be interested in

If 80 pounds cost $4.80 how much does 150 pounds cost.

fgiga [73]

Answer:

Step-by-step explanation:

80 pounds : 480 cents

1 pound : 6 cents

480÷80=6

1 pound : 6 cents

150 pounds : $9

150×6= 900 cents

900 cents= $9

Please mark branliest :)

8 0

2 years ago

In a class of 7, there 4 syudents who play soccer. If the teacher chooses 3 students, what is the probability that none of the t

Lubov Fominskaja [6]

Answer:

75%

Step-by-step explanation:

Do 3/4 multiplied by 100% (100/100)

Then you get 75/100 which is 75%.

3 0

2 years ago

At Buffalo Mild Wings, the price of chicken wings depends on the number of wings that you order.

Hitman42 [59]

Answer:

Step-by-step explanation:

Look at the numbers.

Sorry, I didnt answer quicker

8 0

3 years ago

Hey! I need this pretty fast- just do the first one though! Thank you! :)

Karolina [17]

Step-by-step explanation:

A. part 1: $1.49 for 6 pencils

1 pencil would cost $1.49 / 6 = $0.24833(5s.f.) = $0.25 (nearest cent)

part 2: $4.60 for 20 pencils

1 pencil would cost $4.60 / 20 = $0.23

best value: part 2 (20pencil pack)

If you wish to explore more into mathematics you can give me a follow on Instagram (learntionary) I'll be regularly posting notes and tips for mathematics

4 0

2 years ago

John looked at his bank account and noticed that he had $2,029.90 in his account. All that he could remember is that he created

Over [174]

We will have that for the previous year, he had in the account:

$m_{y6}=2029.90-\frac{2029.90\cdot6}{100}\Rightarrow m_{y6}=1908.106$

For the year previous to that one, he had:

$m_{y5}=1908.106-\frac{1908.106\cdot6}{100}\Rightarrow m_{y5}=1793.61964$

For the previous year to that, he had:

$m_{y4}=1793.61964-\frac{1793.61964\cdot6}{100}\Rightarrow m_{y4}=1686.002462$

For the year previous to that one, he had:

$m_{y3}=1686.002462-\frac{1686.002462\cdot6}{100}\Rightarrow m_{y3}=1584.842314$

For the second year that the money was in the account, there was:

$m_{y2}=1584.842314-\frac{1584.842314\cdot6}{100}\Rightarrow m_{y2}=1489.751775$

And the orinial ammount of money that was in the account was:

$m_{y1}=1489.751775-\frac{1489.751775\cdot6}{100}\Rightarrow m_{y1}=1400.366669$

From this, we know that Jhon had originally $1400.37 in the bank account.

6 0

8 months ago