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Phoenix [80]
3 years ago
10

Tobias said that his cerebrum is used to make his stomach digest food. Do you agree with Tobias? Explain why or why not in 1-2 s

entences.
Biology
1 answer:
Ugo [173]3 years ago
6 0

Answer:

no

Explanation:

because cerebrum is the part of the brain that processes information or intellectual skills in general. Digestion is a vital automatic function that is managed by a part of the nervous system called brain stem.

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Explain how the original source of energy for egrets, and all the other consumers , is the sun
Maslowich
The term cell growth is used in the contexts of biological cell development and cell division (reproduction). When used in the context of cell division, it refers to growth of cell populations, where a cell, known as the "mother cell", grows and divides to produce two "daughter cells" (M phase). When used in the context of cell development, the term refers to increase in cytoplasmic and organelle volume (G1 phase), as well as increase in genetic material (G2 phase) following the replication during S phase.[1]

Contents
Cell populations Edit

Cell populations go through a particular type of exponential growth called doubling. Thus, each generation of cells should be twice as numerous as the previous generation. However, the number of generations only gives a maximum figure as not all cells survive in each generation.

Cell size Edit

Cell size is highly variable among organisms, with some algae such as Caulerpa taxifolia being a single cell several meters in length.[2] Plant cells are much larger than animal cells, and protists such as Paramecium can be 330 μm long, while a typical human cell might be 10 μm. How these cells "decide" how big they should be before dividing is an open question. Chemical gradients are known to be partly responsible, and it is hypothesized that mechanical stress detection by cytoskeletal structures is involved. Work on the topic generally requires an organism whose cell cycle is well-characterized.

Yeast cell size regulation Edit
The relationship between cell size and cell division has been extensively studied in yeast. For some cells, there is a mechanism by which cell division is not initiated until a cell has reached a certain size. If the nutrient supply is restricted (after time t = 2 in the diagram, below), and the rate of increase in cell size is slowed, the time period between cell divisions is increased.[3] Yeast cell-size mutants were isolated that begin cell division before reaching a normal/regular size (wee mutants).[4]


Figure 1:Cell cycle and growth
Wee1 protein is a tyrosine kinase that normally phosphorylates the Cdc2 cell cycle regulatory protein (the homolog of CDK1 in humans), a cyclin-dependent kinase, on a tyrosine residue. Cdc2 drives entry into mitosis by phosphorylating a wide range of targets. This covalent modification of the molecular structure of Cdc2 inhibits the enzymatic activity of Cdc2 and prevents cell division. Wee1 acts to keep Cdc2 inactive during early G2 when cells are still small. When cells have reached sufficient size during G2, the phosphatase Cdc25 removes the inhibitory phosphorylation, and thus activates Cdc2 to allow mitotic entry. A balance of Wee1 and Cdc25 activity with changes in cell size is coordinated by the mitotic entry control system. It has been shown in Wee1 mutants, cells with weakened Wee1 activity, that Cdc2 becomes active when the cell is smaller. Thus, mitosis occurs before the yeast reach their normal size. This suggests that cell division may be regulated in part by dilution of Wee1 protein in cells as they grow larger.

Linking Cdr2 to Wee1 Edit
The protein kinase Cdr2 (which negatively regulates Wee1) and the Cdr2-related kinase Cdr1 (which directly phosphorylates and inhibits Wee1 in vitro)[5] are localized to a band of cortical nodes in the middle of interphase cells. After entry into mitosis, cytokinesis factors such as myosin II are recruited to similar nodes; these nodes eventually condense to form the cytokinetic ring.[6] A previously uncharacterized protein, Blt1, was found to colocalize with Cdr2 in the medial interphase nodes. Blt1 knockout cells had increased length at division, which is consistent with a delay in mitotic entry. This finding connects a physical location, a band of cortical nodes, with factors that have been shown to directly regulate mitotic entry, namely Cdr1, Cdr2, and Blt1.

Further experimentation with GFP-tagged proteins and mutant proteins indicates that the medial cortical nodes are formed by the ordered, Cdr2-dependent assembly of multiple interacting proteins during interphase. Cdr2 is at the top of this hierarchy and works upstream of Cdr1 and Blt1.[7] Mitosis is promoted by the negative regulation of Wee1 by Cdr2. It has also been shown that Cdr2 recruits Wee1 to the medial cortical node. The mechanism of this recruitment has yet to be discovered. A Cdr2 kinase mutant, which is able to localize properly despite a loss of function in phosphorylation, disrupts the recruitment of Wee1 to the medial cortex and delays entry into mitosis. Thus, Wee1 localizes with its inhibitory network, which demonstrates that mitosis is controlled through Cdr2-dependent negative regulation of Wee1 at the medial cortical nodes.[7]

Cell polarity factors
4 0
3 years ago
does the presence of introns exons in eukaroytic cells provide more potentia diversity in gene products than is possible in pork
Leona [35]

Answer: Yes. Splicing can be done in different ways to yield different mRNAs wich will create different proteins. Prokaryotes are not able to do this.

Explanation:

DNA (deoxyribonucleic acid) is a molecule that contains the genetic information for synthesizing amino acids that form proteins. To do this, DNA must first be transcribed into RNA (ribonucleic acid) and this is the molecule used for protein synthesis (translation). The newly transcribed RNA (called primary messenger RNA) from DNA results in a very long molecule and also has regions that do not code for anything, called introns, which are removed by a process called splicing. Exons are segments in the RNA that do code for amino acids and remain in the mature mRNA after splicing.

<u>Splicing is a process by which introns are cleaved from the primary messenger RNA and exons are joined to generate mature messenger RNA.</u> In addition, alternative splicing occurs which allows different mRNA isoforms and thus different proteins to be obtained from a primary mRNA transcript. This is because the exons will be joined or spliced in different ways, giving rise to different mature messenger RNA sequences. This process occurs mainly in eukaryotes, although it can also be observed in viruses. But it does not take place in Prokaryotes (Bacteria).

In summary, exons/introns can be spliced together in different ways to yield different mRNAs sequences. Each different mRNA sequence will code for a different protein.

6 0
3 years ago
A nucleotide consists of a phosphate group, a pentose sugar, and a __________________, all linked together by covalent bonds. po
solong [7]

Answer:

d. nitrogen-containing base .

Explanation:

A nucleotide comprises a phosphate group, a pentose sugar and a nitrogenous base (nitrogen-containing base).

A nitrogenous base is a type of aromatic heterocyclic organic compound which essentially has nitrogen in it. The base can be a purine or pyrimidine. Purine nitrogenous bases are adenine (A) and guanine (G) while pyrimidine nitrogenous bases are cytosine (C), thiamine (T) and uracil (U).

Till the time a base is not attached to covalently linked phosphate group and a pentose sugar, it is known as nucleoside. But as soon as we attach any nitrogenous base to the nucleoside, a nucleotide is formed. So it means a nucleotide is nucleoside + nitrogenous base.

Examples are as under:

A nucleotide which has adenine as nitrogenous base is known as adenosine triphosphate (ATP) while a nucleotide which has guanine as nitrogenous base is known as Guanosine-5'-triphosphate (GTP).

7 0
3 years ago
If a Killer whale is feeding at the fourth trophic level, how much phytoplankton mass is required to add each gram of new mass t
Ksivusya [100]
In order to add one gram of mass, the whale must consume a sufficient amount of energy. The energy transferred to the fourth trophic level is 0.1⁴ = 0.0001
We divide the mass to be gained by the energy obtained per unit mass, to find the total mass to be eaten:
1 / 0.0001 = 10,000 grams of phytoplankton must be consumed to add one gram of mass.
8 0
3 years ago
What are three differences between dna and rna?
Gelneren [198K]
DNA
1. Found in nucleus
2. Sugar is deoxyribose
3. Bases are A, T, C, and G
RNA
1. Found in nucleus and cytoplasm
2. Sugar is ribose
3. Bases are A, U, C, and G
8 0
3 years ago
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