Answer:
<u>Solution</u><u> </u><u>given</u><u>:</u>
<u>one</u><u> </u><u>side</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>triangle</u><u> </u><u>must</u><u> </u><u>be</u><u> </u><u>less</u><u> </u><u>than</u><u> </u><u>the</u><u> </u><u>sum</u><u> </u><u>of</u><u> </u><u>two</u><u> </u><u>other</u><u> </u><u>side</u><u> </u><u>.</u>
<u>by</u><u> </u><u>making</u><u> </u><u>these</u><u> </u><u>sense</u><u>:</u>
3<10+20
10<20+3
20<10+3not true
these three side are not possible.
again
10<20+25
20<25+10
25<20+10
these three side are true so
required side are:
Side 1:10
Side 2:25
Side 3:20
Answer:
C. 5 is solution of the inequality: B>2.1
Given:
angle ECB=51 degrees
=>
angle EOB = 2*angle ECB = 2*51 = 102 degrees = arc EAB
Also given minor arc AB = 72 degrees
therefore
minor arc EA = 102-72=30 degrees
The answer is a^2 + 5a - 104 I think
Answer: 6.7
Have a good day :D
