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xenn [34]
3 years ago
14

Gayle is making gift bags and must tie 250 ribbons to them. If Gayle can tie 4 ribbons every 10 minutes, how long will it take G

ayle to tie all 250 ribbons?
Mathematics
1 answer:
mart [117]3 years ago
4 0

Answer:

625 minutes

Step-by-step explanation:

Given that:

Time taken to tie 4 ribbons = 10 minutes

Number of ribbons to be tied = 250

To find:

Time taken to tie 250 ribbons.

Solution:

First of all, we need to find the time taken to tie one ribbon.

And then we can multiply it with 250 to find the time taken to tie all the 250 ribbons.

For finding the time to tie one ribbon, we need to divide the time taken to tie 4 ribbons with 4.

Time taken to tie 1 ribbon = \frac{10}{4} = 2.5 minutes

Time taken to tie 250 ribbons = 2.5 \times 250 = <em>625 minutes</em>

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Perimeter = Length+Length+Width+Width
OR
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Answer:

a) The study is an observational study

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d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

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95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

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e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

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