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eduard
3 years ago
13

Simplify 3 whole number 1/6 + 1 whole number 1/4 -2 whole number 2/3​

Mathematics
2 answers:
nexus9112 [7]3 years ago
5 0

Answer:

1 whole 3/4 or 1.75

Step-by-step explanation:

3 \frac{1}{6} + 1\frac{1}{4} -2\frac{2}{3} = \frac{19}{6} + \frac{5}{4} - \frac{8}{3}

                    = \frac{(19 \times 2) + ( 5 \times 3 ) - (8 \times 4)}{12}\\\\=\frac{38+15-32}{12}\\\\=\frac{21}{12} \\\\=\frac{7}{4}\\\\=1 \frac{3}{4}

amid [387]3 years ago
3 0
I believe it will be 1.75
Hope this helps!
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does not exist

Step-by-step explanation:

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Julie is roller skating. She can skate 16 mile in 2 minute. What is Julie's rate in miles per minute?
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8 miles per minute?
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The population of bacteria in a petri dish doubles every 24 h. The population of the bacteria is initially 500 organisms. How lo
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Answer:

16.34 hours

Step-by-step explanation:

According to the given information we can see that the case is of exponential growth

Hence, we will use the formula

A=P(2)^\frac{t}{24}

Here A =800 is the amount that is needed to reach

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We have to find the time it will take to reach 800 that is we need to find t

On substituting the values in the formula we get

800=500(2)^\frac{t}{24}

On simplification we get

\Rightarrow\frac{8}{5}=(2)^\frac{t}{24}

Taking log on both sides we get

\Rightarrow\log\frac{8}{5}=\log(2)^\frac{t}{24}

using \log\frac{m}{n}=\log m-\log n

And \log a^m=m\log a

\Rightarrow\log{8}-\log{5}=\frac{t}{24}\log2

Now substituting values of log 8=0.903, log 5=0.698 and log 2=0.301 we get

\Rightarrow 0.903-0.698=\frac{t}{24}0.301

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3 years ago
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3 0
3 years ago
Evaluate the surface integral:S
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Assuming S does not include the plane z=0, we can parameterize the region in spherical coordinates using

\mathbf r(u,v)=\left\langle3\cos u\sin v,3\sin u\sin v,3\cos v\right\rangle

where 0\le u\le2\pi and 0\le v\le\dfrac\pi/2. We then have

x^2+y^2=9\cos^2u\sin^2v+9\sin^2u\sin^2v=9\sin^2v
(x^2+y^2)=9\sin^2v(3\cos v)=27\sin^2v\cos v

Then the surface integral is equivalent to

\displaystyle\iint_S(x^2+y^2)z\,\mathrm dS=27\int_{u=0}^{u=2\pi}\int_{v=0}^{v=\pi/2}\sin^2v\cos v\left\|\frac{\partial\mathbf r(u,v)}{\partial u}\times \frac{\partial\mathbf r(u,v)}{\partial u}\right\|\,\mathrm dv\,\mathrm du

We have

\dfrac{\partial\mathbf r(u,v)}{\partial u}=\langle-3\sin u\sin v,3\cos u\sin v,0\rangle
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So the surface integral is equivalent to

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=\displaystyle486\pi\int_{v=0}^{v=\pi/2}\sin^3v\cos v\,\mathrm dv
=\displaystyle486\pi\int_{w=0}^{w=1}w^3\,\mathrm dw

where w=\sin v\implies\mathrm dw=\cos v\,\mathrm dv.

=\dfrac{243}2\pi w^4\bigg|_{w=0}^{w=1}
=\dfrac{243}2\pi
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