Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO  ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
 
        
             
        
        
        
Problem 1
subtract 3 x
5y=-3x+11
divide 5
y=3/5x+2.2'
Problem 2
add 5x
7y=5x+9
divide 7
y=5/7x+1.3'
'notice'
you can put 2.2 into a fraction (11/5) and 1.3 (9/7) if your teacher allows it, but i put them into decimals
 
        
             
        
        
        
Answer: si no si no si no
Step-by-step explanation:
 
        
                    
             
        
        
        
19:76*100 =
( 19*100):76 =
1900:76 = 25%