Match each object with the characteristics it represent

Mathematics

1 answer:

Aleks [24]3 years ago

6 0

We need the object and the characteristics.

You might be interested in

What is 19/25 as decimal

Radda [10]

Well first we need to find how we can turn 25 into 100
Well one way would be to multiply by 4
25 x 4 = 100

Since we multiplied the bottom number by 4 we should multiply the top number by 4.

So..
19 x 4 = 76

So our new fraction is..
76
-----
100

Now we can easily turn this into a decimal.
76/100 = 0.76

Answer = 0.76

Good Luck! :)

3 0

3 years ago

Read 2 more answers

Help i brian list<br> vvvv

Thepotemich [5.8K]

I think it’s A Im not sure tho

6 0

2 years ago

Read 2 more answers

Mr.Davis's students were surveyed on their favorite subject. One fifth prefer math, 0.35 prefer social studies, and 45% prefer r

lara [203]

its already in order

7 0

3 years ago

Read 2 more answers

Graph 24x+25=−6y+7 .

MrRa [10]

Okay, So you have 24x+25=6y+7

Step 1: Pull out like factors : 24x + 18 + 6y = 6 • (4x + y + 3)

Step 2: 4x+y+3 = 0

y-intercept = -3/1 = -3.00000

x-intercept = -3/4 = -0.75000

Slope = -8.000/2.000 = -4.000

And bam, you have a straight line

5 0

3 years ago

The point (1, −1) is on the terminal side of angle θ, in standard position. What are the values of sine, cosine, and tangent of

Lilit [14]

Check the picture below.

$\bf (\stackrel{a}{1}~,~\stackrel{b}{-1})\qquad \impliedby \textit{let's find the hypotenuse} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c = \sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ c=\sqrt{1^2+(-1)^2}\implies c=\sqrt{2} \\\\[-0.35em] ~\dotfill$

$\bf sin(\theta ) \implies \cfrac{\stackrel{opposite}{-1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{-1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies -\cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies -\cfrac{\sqrt{2}}{2}$

$\bf cos(\theta ) \implies \cfrac{\stackrel{adjacent}{1}}{\stackrel{hypotenuse}{\sqrt{2}}}\implies \cfrac{1}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies \cfrac{\sqrt{2}}{(\sqrt{2})^2}\implies \cfrac{\sqrt{2}}{2} \\\\\\ tan(\theta ) = \cfrac{\stackrel{opposite}{-1}}{\stackrel{adjacent}{1}}\implies tan(\theta ) = -1$

7 0

3 years ago

Read 2 more answers