For this case we have that by definition, the roots, or also called zeros, of the quadratic function are those values of x for which the expression is 0.
Then, we must find the roots of:
Where:
We have to:
Substituting we have:
By definition we have to:
So:
Thus, we have two roots:
Answer:
You need it to be solved?
Find the Greatest Common Factor (GCF)
<u>GCF = 6y^6</u>
Factor out the GCF. (Write the GCF first. Then, in parenthesis divide each term by the GCF.)
6y^6(24y^8/6y^6 + 6y^6/6y^6)
Simplify each term in parenthesis
<u>6y^6(4y^2 + 1)</u>
First step is to distribute.
-4a^2 - 6a +2 + 3a^2 -3
Combine like terms
-a^2 -6a -1
