The picture in the attached figure

step 1
we know that
It is given that AD and BD are bisectors of ∠CAB and ∠CBA respectively.
Therefore,
x = ∠CAB/2 -----> equation 1
y = ∠CBA/2 -----> equation 2

step 2
In triangle ABC,
∠CAB + ∠CBA + ∠ACB = 180° ----> [The sum of all three angles of a triangle is 180°]
∠CAB + ∠CBA + 110° = 180°
∠CAB + ∠CBA = 180° - 110°
∠CAB + ∠CBA = 70° ------> divide by 2 both sides
∠CAB/2 + ∠CBA/2 = 70/2 -------> equation 3
substitute equation 1 and equation 2 in equation 3
x+y=35

hence

the answer is
x+y =35°
⇒ x + y = 35° ...[From equation (1) and (2)]

5 0

4 years ago

(WILL GIVE BRAINLIEST)

weeeeeb [17]

Answer:

m<I=57

m<J=57

m<K=66

Step-by-step explanation:

All the angles in a triangle add up to 180 degrees.

m<I= 3x+18

m<K= 5x+1

m<I is congruent to m<J.

We can plug the information we already know into the equation.

3x+18+3x+18+5x+1=180

11x+37=180

Subtract 37 from both sides.

11x=143

x=13

Now, we can find out what the angles are.

m<I= 3x+18

m<I=3(13)+18

m<I=39+18

m<I=57

We know that m<I=m<J, so they are both equal to 57 degrees.

m<J=57

Now for m<K:

m<K=5x+1

m<K=5(13)+1

m<K=65+1

m<K=66

We know this is correct because 57+57+66=180.

4 0

3 years ago