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3 years ago

7

The perimeter of the rectangle is 32 m one side is 11 m long what is the length of the missing side

1 answer:

Minchanka [31]3 years ago

8 0

Answer:

The length of the missing side is 5 m

Step-by-step explanation:

In order to find this, use the perimeter formula.

P = 2L + 2W

Now input 11 as the L and 32 as P

32 = 2(11) + 2W

32 = 22 + 2W

10 = 2W

5 = W

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2 years ago

If f(x) = 5x, what is f -1 (x) ?

Gala2k [10]

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Step-by-step explanation:

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1 year ago

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2 years ago

Read 2 more answers

Use the rules of exponents to simplify the expressions. Match the expression with its equivalent value.

Lelechka [254]

Answer:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}} = 32$

Step-by-step explanation:

1) $\frac{(-2)^{-5}}{(-2)^{-10}}$

Solving using exponent rule: $a^{-m}=\frac{1}{a^m}$

$\frac{(-2)^{-5}}{(-2)^{-10}}\\=(-2)^{-5+10}\\=(-2)^{5}\\=-32$

So, $\frac{(-2)^{-5}}{(-2)^{-10}}=-32$

2) $2^{-1}.2^{-4}$

Using the exponent rule: $a^m.a^n=a^{m+n}$

We have:

$2^{-1}.2^{-4}\\=2^{-1-4}\\=2^{-5}$

We also know that: $a^{-m}=\frac{1}{a^m}$

Using this rule:

$2^{-5}\\=\frac{1}{2^5}\\=\frac{1}{32}$

So, $2^{-1}.2^{-4} = \frac{1}{32}$

3) $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2$

Solving:

$(-\frac{1}{2} )^3.(-\frac{1}{2} )^2\\=(-\frac{1}{8} ).(\frac{1}{4} )\\=-\frac{1}{32}$

So, $(-\frac{1}{2} )^3.(-\frac{1}{2} )^2=-\frac{1}{32}$

4) $\frac{2}{2^{-4}}$

We know that: $a^{-m}=\frac{1}{a^m}$

$\frac{2}{2^{-4}}\\=2\times 2^4\\=2(16)\\=32$

So, $\frac{2}{2^{-4}} = 32$

3 0

2 years ago

Simplify this expression HELP ASAP

Sergio039 [100]

Answer:

B

Step-by-step explanation:

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$\sqrt{a}$ × $\sqrt{b}$ = $\sqrt{ab}$

Given

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Each term in the second factor is multiplied by each term in the first factor

= $\sqrt{2}$ ( $\sqrt{5}$ - $\sqrt{7}$ ) + $\sqrt{3}$ ( $\sqrt{5}$ - $\sqrt{7}$ ) ← distribute parenthesis

= $\sqrt{10}$ - $\sqrt{14}$ + $\sqrt{15}$ - $\sqrt{21}$

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3 years ago