Question

What is the equation of a line that passes through the point (2, 7) and is perpendicular to the line whose equation is y=x/4+5 ?

Answer 1

Answer:

y = -4x+15

Step-by-step explanation:

y=x/4+5 may be presented as y = 1/4 x + 5, where a=1/4, b=5

swapping numerator and denominator and inserting an opposite sign in a=1/4, we have:

1/4 --------> 4/1 -------> -4/1 = -4

y = -4x+n

Point (2,7) means that x=2, y=7 substitute it to the equation y=-4x+n, calculate "n":

7=-4*2+n ------>    7=-8+n ------->   7+8 = n -------> 15=n

substituting n=15 to the equation y=-4x+n, we get finally y=-4x+15