What is the equation of a line that passes through the point (2, 7) and is perpendicular to the line whose equation is y=x/4+5 ?

Mathematics

1 answer:

worty [1.4K]3 years ago

8 0

Answer:

y = -4x+15

Step-by-step explanation:

y=x/4+5 may be presented as y = 1/4 x + 5, where a=1/4, b=5

swapping numerator and denominator and inserting an opposite sign in a=1/4, we have:

1/4 --------> 4/1 -------> -4/1 = -4

y = -4x+n

Point (2,7) means that x=2, y=7 substitute it to the equation y=-4x+n, calculate "n":

7=-4*2+n ------> 7=-8+n -------> 7+8 = n -------> 15=n

substituting n=15 to the equation y=-4x+n, we get finally y=-4x+15

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3 years ago

Can you guys help me out

marusya05 [52]

Answer:

a. S = 3n + 2

b. There while be 62 squares.

Step-by-step explanation:

We know the first term of this sequence is 5. To figure out the equation, subtract the following term from the previous. Do you see a common difference?

8 - 5 = 3

11 - 8 = 3

14 - 11 = 3

We're seeing a constant difference of 3 (which makes this an arithmetic sequence), but the first term is 5. That mean something is being added to make the first term 5. Subtract 3 from 5 to get 2. This means 2 is being added to every multiple of 3, which leads us to the equation: S = 3n + 2.

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<em>Multiply 3 by 20, then add 2.</em>

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The 20th term will have 62 squares.

7 0

2 years ago

Solve using any method 4x-y=20 and -2x-2y=10

dsp73

Answer:

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Step-by-step explanation: