Devyn sold 15 boxes of cookies this week. This is 7 more than he sold last week. How many boxes did he sell last week?

HELP PLEASE!! TON OF POINTS. RIGHT ANSWERS ONLY REWARDED. MATH GENIUSES?

Nonamiya [84]

Answer:

The graph is shifted 1 unit right

The graph is shifted 2 units down

Step-by-step explanation:

We are given

Parent function as

$f(x)=2^{x+3}-3$

New function as

$g(x)=2^{x+2}-1$

we can also write as

$g(x)=2^{x+3-1}-3+2$

We can see that

1 is subtracted to x-value

and 2 is added to y-value

So, f(x) is shifted right by 1 unit

and

f(x) is shifted up by 2 unit

3 0

3 years ago

a new machine with better technology produces 210 gel pens every 15 minutes what is the concept of the proportionality in the re

Helen [10]

Answer:

p = 14t

Step-by-step explanation:

y = kx

The rate k = 210 ÷ 15 = 14 gel pens per minute

"p" is number of pens, "t" is number of minutes

p = 14t

4 0

3 years ago

If AC is parallel to DE, find X

UNO [17]

Answer: x = 50

Concept:

Here, we need to know the idea of alternative interior angles and the angle sum theorem.

Alternative interior angles are angles that are formed inside the two parallel lines, and the values are equal.

The angle sum theorem implies that the sum of interior angles of a triangle is 180°

If you are still confused, please refer to the attachment below or let me know.

Step-by-step explanation:

Given information:

AC ║ DE

∠ABC = 85°

∠A = 135°

Find the value of ∠BAC

∠A + ∠BAC = 180° (Supplementary angle)

(135°) + ∠BAC = 180°

∠BAC = 45°

Find the value of ∠BCA

∠ABC + ∠BAC + ∠BCA = 180° (Angle sum theorem)

(85°) + (45°) + ∠BCA = 180°

∠BCA = 50°

Find the value of x (∠EBC)

∠EBC ≅ ∠BCA (Alternative interior angles)

Since, ∠BCA = 50°

Therefore, ∠EBC = 50°

$\Large\boxed{x=50}$

Hope this helps!! :)

Please let me know if you have any questions

8 0

1 year ago

Find the value of x² - x+1 when x=√3 -1, in the form a+b√3 where a and b are integers

lidiya [134]

Answer:

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

Step-by-step explanation:

We are given $x=\sqrt{3}-1$ and we are asked to find the value of $x^2-x+1$ .

So we will need to find $x^2$ .

$x=\sqrt{3}-1$

Square both sides:

$x^2=(\sqrt{3}-1)^2$

Expand using identity: $(x-a)^2=x^2-2ax+a^2$ .

$x^2=(\sqrt{3})^2-2(\sqrt{3})(1)+1^2$

$x^2=3-2\sqrt{3}+1$

$x^2=4-2\sqrt{3}$

Let's go back to the full $x^2-x+1$ .

$x^2-x+1$

$(4-2\sqrt{3})-(\sqrt{3}-1)+1$

$4-2\sqrt{3}-\sqrt{3}+1+1$

$6-3\sqrt{3}$

If you compare this to $a+b\sqrt{3}$ , then $a=6$ and $b=-3$ .

5 0

4 years ago

What are two ways to write 2a-18 in words

Rashid [163]

Two A minus eighteen

eighteen minus Two A

6 0

3 years ago