7cos(x) + 1 = 6sec(x)
7cos(x) + 1 = 6/cos(x)
7cos^(x) + cos(x) = 6
7cos^(x) + cos(x) - 6 = 0
[7cos(x) - 6][cos(x) + 1] = 0
cos(x) = 6/7 , x = arccos(6/7) and
cos(x) = -1, x = 180

6 0

3 years ago

What are the answers to these thank you and please tell me how to get it

mote1985 [20]

5-3(1/2x+2)=-7
-3(1/2x+2)=-7-5
(1/2x+2)=4
1/2x=2
x=4
just to give u an idea

4 0

3 years ago

How do you identify if the equation is linear, exponential, or quadratic?

Naddika [18.5K]

Answer:

It's form. Linear is a normal line, exponential is a curvy line, and quadratic is a u shape with the vertice on the y-axis line, making half of the u on the left quadrant and the other half on the right quadrant

Step-by-step explanation:

first is linear, second is exponential and third is quadratic

8 0

3 years ago

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