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3 years ago

Which of these characteristics do a rhombus and a rectangle always have in common?

Mathematics

2 answers:

lutik1710 [3]3 years ago

7 0

Answer:

opposite sides with equal length

hope it helps

Alexxandr [17]3 years ago

5 0

Opposite sides with equal length

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Help.........................

garri49 [273]

<h3>Answer: Choice A</h3>

$x^2\left(\sqrt[4]{x^2}\right)$

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

$\sqrt[4]{x} = x^{1/4}$

The same applies to x^10 as well

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}$

Multiply the exponents 10 and 1/4 to get 10/4

$\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}$

$\sqrt[4]{x^{10}} = x^{10/4}$

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If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

$x^{m/n} = x^a\sqrt[n]{x^b}$

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

$x^{m/n} = x^a\sqrt[n]{x^b}$

turns into

$x^{10/4} = x^2\sqrt[4]{x^2}$

which means

$\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}$

7 0

3 years ago

Can someone -that knows how to calculate how many gallons of paint will cover a room- help me??

never [62]

Answer:

try option D that should be correct

Step-by-step explanation:

5 0

3 years ago

A theater group is having a carwash fundraiser. The group can only wash 45 cars with the amount of soap they purchased. Each car

Vesnalui [34]

Answer:

<h2>The domain for this function is $c > 0$ where $c \in Z$ .</h2>

Step-by-step explanation:

The given function is

$f(c)=7c$

Where $c$ represents cars. This function models the profits they make.

Now, as you can deduct already, we can define to different domains, the mathematical one and the reasonable one.

The reasonable domain is about all the useful values to the problem. For example, as we are talking about car, they can't wash -5 cars, so negative numbers are excluded. Similarly, they can't wash 6.75 cars, because that would imply an incomplete job.

Therefore, the domain for this function is $c > 0$ where $c \in Z$ .

(Notice that we specify that the independent valur can only use whole positive numbers only).

5 0

3 years ago

The half-life of the isotope Osmium-183 is 12 hours. Choose the equation below that gives the remaining mass of Osmium-183 in gr

raketka [301]

The given equations are incomprehensible, I'm afraid...

You're given that osmium-183 has a half-life of 12 hours, so for some initial mass M₀, the mass after 12 hours is half that:

1/2 M₀ = M₀ exp(12k)

for some decay constant k. Solve for this k :

1/2 = exp(12k)

ln(1/2) = 12k

k = 1/12 ln(1/2) = - ln(2)/12

Now for some starting mass M₀, the mass M remaining after time t is given by

M = M₀ exp(kt )

So if M₀ = 590 g and t = 36 h, plugging these into the equation with the previously determined value of k gives

M = 590 exp(36k) = 73.75

so 73.75 ≈ 74 g of Os-183 are left.

Alternatively, notice that the given time period of 36 hours is simply 3 times the half-life of 12 hours, so 1/2³ = 1/8 of the starting amount of Os-183 is left:

590/8 = 73.75 ≈ 74

6 0

3 years ago

To solve 4÷13, Matthew thinks about blocks that each weigh 13 pound and how many blocks he would need to put on a scale so that

Katarina [22]

3.25 if you round it it’ll be 3.3

4 0

2 years ago