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3 years ago

2/6 + _ =1 explain how you can find the unknown addend

Mathematics

2 answers:

Leya [2.2K]3 years ago

7 0

Hi there!

To find the unknown addend, we can just subtract:

1 - 2/6 = 4/6
4/6 = 2/3

Hope this helps!

Vlad [161]3 years ago

6 0

2/6 + 2/3 = 1

To find this, you would replace the blank with a variable (x), and calculate.

2/6 simplified is 1/3

1 - 1/3 = 2/3

Hope this helped. ♡

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Please help meh i dont know the answer

Savatey [412]

Answer:

3 inches

Step-by-step explanation: An equilateral triangle means all 3 sides are the same length.

A square also have the same length for all 4 sides.

So each side of the square is 6cm, to find the perimeter you do 6*4=24.

then divide the square's perimeter by 3 since triangle have 3 sides. 24/3=8

so each side of the triangle will be 8cm

7 0

3 years ago

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago

The arch of a bridge forms the upper half of an ellipse. The arch is 6 meters above the 20-meter-wide river. Write an equation f

aksik [14]

Answer:

$\frac{x^2}{36} + \frac{y^2}{100} = 1$

Step-by-step explanation:

Required

The equation of the ellipse

This is calculated as:

$\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$

Where:

$b =6$ ---- height

$a = 0.5 * 20 =10$ --- width

So:

$\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$

$\frac{x^2}{6^2} + \frac{y^2}{10^2} = 1$

$\frac{x^2}{36} + \frac{y^2}{100} = 1$

3 0

3 years ago

Given (1, -3) and (5, 1). The slope of the line is The equation of the line is

guapka [62]

To find the slope of the line we can use the following formula:

$\frac{y.2 - y.1}{x.2 - x.1} = m$

1 - (-3)/5 - 1

4 / 4

<h3>The slope of the line is equal to 1.</h3>

To find the equation, we can just use slope-intercept form.

We already know the slope, so our current equation is y = x

By knowing the slope, we can apply the slope to our lowest pair of coordinates to find the y value when x = 0.

Subtract 1 from the x and y values of (1, -3)

(0, -4) is our new point, and so we know the y-intercept is -4.

<h3>Our equation for the line is y = x - 4</h3>

4 0

3 years ago

Find the approximate value of 191−−−√ to the nearest tenth. What 2 numbers does it fall between when placed on a number line? Qu

PolarNik [594]

Answer:

13.5-14

Step-by-step explanation:

it is 13.8

8 0

3 years ago