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3 years ago

For two functions, m(x) and p(x), a statement is made that m(x) = p(x) at x = 7. What is definitely true about x = 7? (2 points)

2 answers:

7 0

A)Both m(x) and p(x) cross the x-axis at 7.
B)Both m(x) and p(x) cross the y-axis at 7.
C)Both m(x) and p(x) have the same output value at x = 7.
D)Both m(x) and p(x) have a maximum or minimum value at x = 7.

m(x) = p(x) at x = 7

True statement about x = 7.
C)Both m(x) and p(x) have the same output value at x = 7.

Alexeev081 [22]3 years ago

5 0

Answer: Its true that it but equals 7

Step-by-step explanation:

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Tres multiplicaciones de seis factores:una en la que el resultado sea positivo,otra en la que sea negativo,y una cuyo resultado

Free_Kalibri [48]

Answer:

Vamos a inventa tres multiplicaciones de seis factores en la que el resultado sea positivo, es decir un número mayor que cero, en la otra negativo, es decir, un número menor que cero y por último otra multiplicación que de como resultado el cero "0".

Primero recordemos que:

Los factores son los números que se multiplican.

Seis factores serían 6 números.

Multiplicación con resultado positivo, es decir mayor a 0:

2×3×4×2×1×5=240

Multiplicación con resultado negativo, es decir menor a 0:

-4×2×5×2×1×10= -400

Multiplicación con resultado cero:

2×4×6×7×11×0=0

Step-by-step explanation:

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2 years ago

The owner of a cattle ranch would like to fence in a rectangular area of 3000000 m^2 and then divide it in half with a fence dow

Reika [66]

If you notice the picture below, the amount of fencing, or perimeter, that will be used will be 3w + 2l

now $\bf \begin{cases}
A=l\cdot w\\\\\
A=3000000\\
----------\\
3000000=l\cdot w\\\\
\frac{3000000}{w}=l
\end{cases}\qquad thus
\\\\\\
P=3w+2l\implies P=3w+2\left( \cfrac{3000000}{w} \right)\implies P=3w+\cfrac{6000000}{w}
\\\\\\
P=3w+6000000w^{-1}\\\\
-----------------------------\\\\
now\qquad \cfrac{dP}{dw}=3-\cfrac{6000000}{w^2}\implies \cfrac{dP}{dw}=\cfrac{3w^2-6000000}{w^2}
\\\\\\
\textit{so the critical points are at }
\begin{cases}
0=w^2\\\\
0=\frac{3w^2-6000000}{w^2}
\end{cases}$

solve for "w", to see what critical points you get, and then run a first-derivative test on them, for the minimum

notice the $0=w^2\implies 0=w$ so. you can pretty much skip that one, though is a valid critical point, the width can't clearly be 0

so.. check the critical points on the other

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3 years ago

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klemol [59]

Answer:

f − 1(x)=x−2 if you are talking about the inverse

please comment what is the purpose of this excersise so i can help you further

Step-by-step explanation:

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3 years ago

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