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mariarad [96]
3 years ago
10

Helpppppppppppppppppppppppppppppppppppppppppppppppppppppp

Mathematics
1 answer:
muminat3 years ago
5 0
The answer is 17.156
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I need help with this ASAP
belka [17]

Answer:

The slope is negative 2  or  (-2)

Step-by-step explanation:

Y2 - Y1

----------

X2 -X1

(0,2)

(1,0)

2 - 0

-------    =  2/-1  = -2

0 - 1

3 0
4 years ago
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Suppose the solutions of a homogeneous system of four linear equations in five unknowns are all multiples of one nonzero solutio
Akimi4 [234]

Consider a homogeneous machine of four linear equations in five unknowns are all multiples of 1 non-0 solution. Objective is to give an explanation for the gadget have an answer for each viable preference of constants on the proper facets of the equations.

Yes, it's miles true.

Consider the machine as Ax = 0. in which A is 4x5 matrix.

From given dim Nul A=1. Since, the rank theorem states that

The dimensions of the column space and the row space of a mxn matrix A are equal. This not unusual size, the rank of matrix A, additionally equals the number of pivot positions in A and satisfies the equation

rank A+ dim NulA = n

dim NulA =n- rank A

Rank A = 5 - dim Nul A

Rank A = 4

Thus, the measurement of dim Col A = rank A = five

And since Col A is a subspace of R^4, Col A = R^4.

So, every vector b in R^4 also in Col A, and Ax = b, has an answer for all b. Hence, the structures have an answer for every viable preference of constants on the right aspects of the equations.

8 0
3 years ago
Financial Literacy Paul earns $25 for grooming a dog plus $18.50
Free_Kalibri [48]

Answer:

e): m=18.50d + 25

Step-by-step explanation:

3 0
3 years ago
A circle has a radius of 7.5 centimeters and a central angle AOB that measures 90 degrees. What is the length of the intercepted
Julli [10]
Since there are 360^{\circ} in a circle, and central \angle AOB = 90^{\circ}, you can see that the part "sliced out" by the central angle is \frac{90^{\circ}}{360^{\circ}} = \frac{1}{4} of the whole circle.

This means that the length of the intercepted arc \stackrel{\frown}{AB} is \frac{1}{4} of the circumference of the circle. So,

\stackrel{\frown}{AB} = \frac{1}{4}(2 \pi r) = \frac{1}{4}(2 \pi (7.5 cm)) = \bf \frac{15 \pi}{4} cm



6 0
3 years ago
One day your parents will die then you will then your children will then your grand children and so on thats how it feels to be
aivan3 [116]

Answer:

Yes that is truth that you have wrote

6 0
3 years ago
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