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xxMikexx [17]
3 years ago
9

To view the contents of a file that was compressed with the bzip2 utility, you must used the ____________________ command.

Computers and Technology
1 answer:
bekas [8.4K]3 years ago
8 0

Answer:

zcat

Explanation:

Zcat is a command line utility for viewing the contents of a compressed file without literally uncompressing it. It expands a compressed file to standard output allowing you to have a look at its contents. In addition, zcat is identical to running gunzip -c command.

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Which option will enable Mina to apply several formats to the spreadsheet cells at the same time?
madam [21]
Applying a cell style will enable Mina to apply several formats to the spreadsheet cells at the same time.  <span>To apply several formats in one step, and to make sure that cells have consistent formatting, you can use a cell style. A cell style is a defined set of formatting characteristics, such as fonts and font sizes, number formats, cell borders, and cell shading. </span>
4 0
3 years ago
The following program is supposed to display a message indicating if the integer entered by the user is even or odd. What is wro
Lapatulllka [165]

Answer:

A. The function definition must appear before the function is called

Explanation:

Given

The above lines of code

Required

Determine the error in the program

In python, functions has be defined before they are called but in this case (of the given program), the function is called before it was defined and this will definitely result in an error;

<em>Hence, option A answers the question</em>

The correct sequence of the program is as follows:

<em>def evenOdd(n): </em>

<em>      if n % 2 == 0: </em>

<em>            return "even" </em>

<em>      return "odd" </em>

<em>num = int(input("Enter an integer: ")) </em>

<em>print("The integer is", evenOdd(num)) </em>

<em />

6 0
2 years ago
Write a program that prompts the user to input a number. The program should then output the number and a message saying whether
Gala2k [10]

Answer:

Following is the program in C++ Language

#include <iostream> // header file

using namespace std; // namespace std

int main() // main method

{

   int n;  // variable declaration

   cout<<" Please enter the number :";

   cin>>n; // Read the number

   if(n>0) // check the condition when number is positive

   {

cout<<n<<endl<<"The number is Positive"; // Display number

   }

  else if(n<0) // check the condition when number is Negative

  {

cout<<n<<endl<<"The number is Negative";// Display number

  }

  else // check the condition when number is Zero

  {

cout<<n<<endl<<"The number is Zero";// Display number

  }

   return 0;

  }

Output:

Please enter the number:

64

The number is Positive

Explanation:

Following are the description of the program

  • Declared a variable "n" of int type.
  • Read the value of "n" by user.
  • Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
  • Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
  • Finally if both the above condition is fail it print the message " The number is Zero"

7 0
3 years ago
Format Painter is used to copy formatting from one location to another.<br> true<br> false
Readme [11.4K]
True

Hope this helps!
4 0
2 years ago
Write a function wordcount() that takes the name of a text file as input and prints the number of occurrences of every word in t
artcher [175]

Answer:

Explanation:

The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.

import re

def wordCount(fileName):

   file = open(fileName, 'r')

   wordList = file.read().lower()

   wordList = re.split('\s', wordList)

   wordDict = {}

   for word in wordList:

       if word in wordDict:

           wordDict[word] = wordDict.get(word) + 1

       else:

           wordDict[word] = 1

   print(wordDict)

wordCount('great_expectations.txt')

4 0
3 years ago
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