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AlekseyPX
2 years ago
10

What is a client benefit of partnering with Accenture's Intelligent Platform Services (IPS)?

Computers and Technology
1 answer:
charle [14.2K]2 years ago
8 0
It’s a bot Bc when you do stuff you can believ it
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9. Select the correct answer.
mihalych1998 [28]

Answer:

I believe the answer is exclusive but im not 100% sure

5 0
3 years ago
The shortest compressed format of the ipv6 address 2001:0db8:0000:1470:0000:0000:0000:0200 is
devlian [24]

The answer is : 2001:DB80:1470::200

A double colon ( :: ) can replace any single, contiguous string of one or more 16-bit segments (hextets) which is  consist of all 0s, and it can only be used once per IPv6 address. Therefore,any leading 0s (zeros) in any 16-bit section or hextet can be omitted.

3 0
3 years ago
How do we make a acount
IRISSAK [1]
Press sign up and put your information in there. Then it should automatically make your profile.
8 0
3 years ago
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Write an algorithm that receives a number from the user (you can store the number in a variable called N). Then the algorithm sh
lbvjy [14]

Answer:

Algorithm:

1. Declare an integer variable N.

2. Read the value N from user.

3.While(N):

 3.1 find r=N%10;

 3.2 print r in new line.

 3.3 Update N as N=N/10.

4.end program.

Implementation in C++.

// header

#include <bits/stdc++.h>

using namespace std;

// main function

int main()

{

// variable

int N;

cout<<"Enter an Integer:";

   cin>>N;

// find the digits of number

   while(N)

   {

       // last digit

       int r=N%10;

       // print last digit

       cout<<r<<endl;

       // update the number

       N=N/10;

}

return 0;

}

Output:

Enter an Integer:329                                        

9                                                          

2                                                          

3

7 0
2 years ago
Which of the following shows a list of Big-Oh running times in order from slowest to fastest?
Rufina [12.5K]

Answer:

O(N!), O(2N), O(N2), O(N), O(logN)

Explanation:

N! grows faster than any exponential functions, leave alone polynomials and logarithm. so O( N! ) would be slowest.

2^N would be bigger than N². Any exponential functions are slower than polynomial. So O( 2^N ) is next slowest.

Rest of them should be easier.

N² is slower than N and N is slower than logN as you can check in a graphing calculator.

NOTE: It is just nitpick but big-Oh is not necessary about speed / running time ( many programmers treat it like that anyway ) but rather how the time taken for an algorithm increase as the size of the input increases. Subtle difference.

5 0
2 years ago
Read 2 more answers
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