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3 years ago

I am confused this question.

Mathematics

1 answer:

aleksandr82 [10.1K]3 years ago

4 0

I'm assuming that they want you to find the measure of the jellybean in fractions of an inch. So, if you count the smallest lines, there are 16 in one inch. Then, count how many small lines long the jellybean is: 9
This means that the jellybean is 9 out of 16 of the 16 small lines long, or 9/16 of an inch!

Hope this helps :)

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Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

3 0

3 years ago

Jim writes 10^4 words every day how many words does he writes in 10^3 days?

Alchen [17]

1,000 words

10^4=10,000
10^3=1,000

7 0

3 years ago

A pyramid has a square base with sides of length s. The height of the pyramid is equal to - of the length of a side on the base.

Vera_Pavlovna [14]

<h3><u>Question:</u></h3>

A pyramid has a square base with sides of length s. The height of the pyramid is equal to 1/2 of the length of a side on the base. Which formula represents the volume of the pyramid?

<h3><u>Answer:</u></h3>

<em><u>The formula represents the volume of the pyramid is:</u></em>

$V=\frac{1}{6}s^3$