Answer:
1507m²
Step-by-step explanation:
Given parameters:
Radius of cylinder = 12m
Height of cylinder = 8m
π = 3.14
Unknown:
Surface Area of cylinder = ?
Solution:
The surface area of any body is the sum of all the area that covers a body.
For a cylinder, the surface area is given as;
SA = 2πr² + 2πrh
Where SA = Surface Area
r = radius of cylinder
h = height of cylinder
Now input the parameters in the given equation and solve;
SA = (2 x 3.14 x 12²) + (2 x 3.14 x 12 x 8)
SA = 904.32 + 603.264
SA = 1507.584m² = 1507m²
Let's isolate x by moving the -1 to the left and the 3/2x to the right (direction chosen so that you don't get negative numbers):
![4 + 1 = 2x - \frac{3}{2}x \implies 5 = \frac{1}{2}x](https://tex.z-dn.net/?f=4%20%2B%201%20%3D%202x%20-%20%5Cfrac%7B3%7D%7B2%7Dx%20%5Cimplies%205%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx)
Now multiply both sides by 2 and swap sides:
Answer:
Therefore the height of the tower is 101.79 m.
Step-by-step explanation:
The ratio of the height of an object to the shadow of the object is always constant at certain time.
![\frac{\textrm{The height of object}}{\textrm{The shadow of the object}}= constant](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctextrm%7BThe%20height%20of%20object%7D%7D%7B%5Ctextrm%7BThe%20%20shadow%20of%20the%20object%7D%7D%3D%20constant)
![\Rightarrow \frac{h_1}{s_1}=\frac{h_2}{s_2}](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cfrac%7Bh_1%7D%7Bs_1%7D%3D%5Cfrac%7Bh_2%7D%7Bs_2%7D)
Given that,the length of the pole is 3.5 m and it casts a shadow that is 1.47 m long.
The length of shadow that castes by a tower is 42.75 m long.
Here h₁= 3.5 m, s₁=1.47 m, h₂= ? and s₂=42.75 m
![\therefore \frac {3.5}{1.47}=\frac{h_2}{42.75}](https://tex.z-dn.net/?f=%5Ctherefore%20%5Cfrac%20%7B3.5%7D%7B1.47%7D%3D%5Cfrac%7Bh_2%7D%7B42.75%7D)
⇒3.5 ×42.75 = h₂× 1.47
![\Rightarrow h_2=\frac{3.5 \times 42.75}{1.47}](https://tex.z-dn.net/?f=%5CRightarrow%20h_2%3D%5Cfrac%7B3.5%20%5Ctimes%2042.75%7D%7B1.47%7D)
⇒h₂ = 101.79 m (approx)
Therefore the height of the tower is 101.79 m.
The question is the which statement describes the relationship between the graph f(x) = 4x and the graph g(x) = f(x) + 3
The answer is option a. the graph of g(x) is translated 3 units up from the graph of f(x).
You can realize that every image of g(x) (this is the y-coordina) is the image of f(x) + 3 units, then all the y-coordinates of g(x) are 3 units upper than the y-coordinates of f(x).