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Elza [17]
3 years ago
15

What is the awnser to the circled equations?​

Mathematics
1 answer:
pshichka [43]3 years ago
5 0

Answer:

y = - \frac{1}{3}x - 1

Step-by-step explanation:

We have to write an equation of a line which  passes through the given point (-9,2) and is perpendicular to the given straight line y = 3x - 12 ........... (1)

Now, equation (1) is in the slope-intercept form and the slope of the line is 3.

Let, m is the slope of the required line.

So, 3m = -1

{Since, the product of the slopes of two perpendicular straight lines is -1}

⇒ m = - \frac{1}{3}

Therefore, the equation of the required line in slope intercept form is  

y = - \frac{1}{3} x + c {Where c is a constant}

Now, this above equation passes through the point (-9,2) point.

So, 2 = -  \frac{1}{3} \times (-9) + c

⇒ 2 = 3 + c

⇒ c = - 1  

Therefore, the equation of the required straight line is y = - \frac{1}{3}x - 1 (Answer)

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Answer:

y = 18  and  x = -2

Step-by-step explanation:

y = x^2+bx+c   To find the turning point, or vertex, of this parabola, we need to work out the values of the coefficients b and c. We are given two different solutions of the equation. First, (2, 0).  Second, (0, -14). So we have a value (-14) for c. We can substitute that into our first equation to find b. We can now plug in our values for b and c into the equation to get its standard form. To find the vertex, we can convert this equation to vertex form by completing the square. Thus, the vertex is (4.5, –6.25). We can confirm the solution graphically     Plugging in  (2,0) :

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2 years ago
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Answer:

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3 years ago
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