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Elza [17]
4 years ago
15

What is the awnser to the circled equations?​

Mathematics
1 answer:
pshichka [43]4 years ago
5 0

Answer:

y = - \frac{1}{3}x - 1

Step-by-step explanation:

We have to write an equation of a line which  passes through the given point (-9,2) and is perpendicular to the given straight line y = 3x - 12 ........... (1)

Now, equation (1) is in the slope-intercept form and the slope of the line is 3.

Let, m is the slope of the required line.

So, 3m = -1

{Since, the product of the slopes of two perpendicular straight lines is -1}

⇒ m = - \frac{1}{3}

Therefore, the equation of the required line in slope intercept form is  

y = - \frac{1}{3} x + c {Where c is a constant}

Now, this above equation passes through the point (-9,2) point.

So, 2 = -  \frac{1}{3} \times (-9) + c

⇒ 2 = 3 + c

⇒ c = - 1  

Therefore, the equation of the required straight line is y = - \frac{1}{3}x - 1 (Answer)

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