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Elenna [48]
3 years ago
6

Look at the figure. Which of the following segments is parallel to AB?

Mathematics
1 answer:
marusya05 [52]3 years ago
5 0
I think it’s c and h
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Suppose c>d. explain why the following inequalities are true:
Aneli [31]

Answer: Optional

Step-by-step explanation:

Since c is greater than d, 2c would be greater than 2d, because when it’s like this 2c

It sometimes means multiply.

7 0
3 years ago
A Teenager can wash two tables per minute write an expression for how many tables they can wash in M minutes
Vikki [24]
The answer to this problem is 2m
3 0
3 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
The Malcolms are taking a trip. Midville is 214 miles
Juliette [100K]

Answer:

642 miles

Step-by-step explanation:

Distance of Midville from their home = 214 miles

Walesburg is 3 times as far.

How far is Walesburg from their home?

Distance of Walesburg from their home = 3 × Distance of Midville from their home

= 3 × 214 miles

= 642 miles

Distance of Walesburg from their home = 642 miles

8 0
3 years ago
1 Selena rewrote the expression 4(5m + 12s) using the distributive property. What expression did Selena create?
ad-work [718]

Answer:

4*5+12

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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