Answer:
The wall is 90 meters wide.
Step-by-step explanation:
1. set up and solve a proportion to find the value of w like this:
1cm=6cm
15m=wm
2. cancel out the like units on both sides of the equation
1=6
15=w
3. Equate the cross products, and then solve for w:
1*w=15*6
w=90 The actual width of the wall is 90 meters.
Answer:
x= 15
Step-by-step explanation:
We can use cross products to solve this problem
7 2x+5
-- = --------
3 x
7x = 3(2x+5)
Distribute
7x = 6x +15
Subtract 6x from each side
7x-6x = 6x-6x+15
x = 15
Answer:
Answer:(0,3)Step-by-step explanation:The solution in a set of graphs is where they intersect. In this graph, they intersect at (0,3)
The amount add to the borrower's monthly payment is $313.33.
Given that lender requires PMI that is 0.8% of the loan amount of $470,000.
A loan's PMI, or personal mortgage insurance, is a type of mortgage insurance used by lenders when making traditional loans such as home loans. A PMI helps cover the loss to the lender (bank) if the borrower stops making monthly mortgage payments on their home loan. Therefore, the PMI can be described as a kind of risk mitigation tool for the bank when the borrower defaults on their EMIs (monthly mortgage payments). So, PMI for a borrower is an additional cost or payment for the borrower on top of his monthly payments i.e. EMI.
Thus, the additional amount of dollars that the borrower has to pay for the PMI on his loan along with his monthly mortgage payments
= Principal Loan amount × (PMI/12)
= $470,000 × (0.8%/12)
= $470,000 × (0.008/12)
= $470,000 × 0.0006666667
=$313.333349
Hence, the additional monthly payment for PMI where lender requires PMI that is 0.8% of the loan amount of $470,000 is $313.33.
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Answer:
Domain : 0 ≤ t ≤ 3
Range : -4 ≤ d ≤ 0
Step-by-step explanation:
The graph attached models the depth of submarine as a function of time.
Points on x-axis represent the time and points on y-axis represent increase in height of the submarine.
Domain of a function is represented by the points on x-axis.
Therefore, Domain : 0 ≤ t ≤ 3
Range of function is represented by te points on y-axis.
Therefore, Range : -4 ≤ d ≤ 0
