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IRISSAK [1]
3 years ago
11

△JKL∼△STU Which statements are true? more than one are right (ps the line means similar to)

Mathematics
2 answers:
drek231 [11]3 years ago
7 0
The correct answers are 

m<J = m<S
<K = <T
KL/TC = JK/ST
arsen [322]3 years ago
4 0

Given:  △JKL∼△STU

When two triangles are similar , then their corresponding sides are proportional and Corresponding angles of one triangle is equal to corresponding angles of another Triangle.

The two Triangles can be similar by following Similarity axiom

1. AA

2. S A S

3. S S S

The Options are

→∠K≅∠T(  True) Corresponding angles are equal.

→JK≅ST (False)

→KL/TU=JK/ST (True) Because sides are proportional.

→JL=SU  (False)

→m∠J=m∠S (True)  Corresponding angles are equal.



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Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
2 years ago
Helppp plssss!!! Thanks!!
faltersainse [42]

The answer is D.

y = x + 1 = 4 + 1 = 5

y = 1/2x + 3 = 1/2(4) + 3 = 2 + 3 =5

4 0
3 years ago
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