This is one of those problems where you'll sink like a rock if
you allow yourself to be blinded by all the useless, unnecessary,
irrelevant information in the first paragraph.
The ONLY information you need is:
-- You're chartering a bus for 1 day.
-- It costs $780 .
That's ALL .
(You don't even need to know that the bus has 55 seats.
You might need that for #8 - #12, but not for #6 or #7.)
_________________________
If the people on the trip are going to share the cost of the bus,
then the cost of each share depends on the number of people.
Less people ==> each one pays more.
More people ==> each one pays less.
Just like everybody in the office sharing the cost of
a birthday gift for the boss.
#6 and #7 should really be done in the reverse order ...
do #7 before you worry about #6.
Before you can fill in the table in #6, you absolutely need
to have the equation, whether or not you realize it.
The total cost is fixed . . . It's $780 .
If 2 people go on the trip, each one pays 780 / 2 .
If 3 people go on the trip, each one pays 780 / 3 .
If 4 people go on the trip, each one pays 780 / 4 .
If 5 people go on the trip, each one pays 780 / 5 .
.
.
If 10 people go on the trip, each one pays 780 / 10 .
.
.
If 20 people go on the trip, each one pays 780 / 20 .
.
.
If ' n ' people go on the trip, each one pays 780 / n .
.
. until the bus is full ...
.
If 55 people go on the trip, each one pays 780 / 55 .
.
If 56 people go on the trip, then you need another bus,
and it gets more complicated.
But up to 55, the price per person is (780 / the number of people).
<span> #7). P = 780 / n .
</span>Now, filling in the table in #6 is a piece 'o cake.<span>
</span>5 people. . . . . . . 780 / 5
10 people . . . . . 780 / 10
15 people . . . . . 780 / 15
20 people . . . . . 780 / 20
.
.
etc.
Just don't go past 55 people. The equation changes after that.
For ANY number of people, even hundreds, and ANY number
of buses, I think the equation looks something like this:
P = (785/n) · [ 1 + int(n/56) ] .
' int ' means ' the greatest integer in ... ', that is,
' throw away the fractional part of the quotient,
and use only the whole number '.
y= mx+b
(16, -7) = (x,y)
2(16) - 3y = 12
32 - 3y = 12
32 - 12 = 3y
20/3 = y
6.6 = y
2x-3(-7) = 12
2x+21 = 12
2x = 12 - 21
x = -9/2
Insert the values into y = mx + b
solve for m and then solve for b
Answer:
(0,-2)
Step-by-step explanation:
substitute in 0 for x
and solve for y
Answer:
3.33 so 3 hours and a half
Step-by-step explanation:
Answer:
-499,485.
Step-by-step explanation:
We can transform this to an arithmetic series by working it out in pairs:
6^2 - 7^2 = (6-7)(6+7) = -13
8^2 - 9^2 = (8-9)*8+9) = -17
10^2 - 11^2 = -1 * 21 = -21 and so on
The common difference is -4.
The number of terms in this series is (998 - 6) / 2 + 1
= 992/2 + 1 = 497.
Sum of n terms of an A.S:
= n/2 [2a1 + (n - 1)d
Here a1 = -13, n = 497, d = -4:
Sum = (497/2)[-26 - 4(497-1)]
= 497/2 * -2010
= -499,485.
