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Zarrin [17]
3 years ago
15

An architect uses a cylindrical container to protect her blueprints. The dimensions of the cylinder shown in the diagram. Which

measurement is closest to the total surface area of the container in square inches?

Mathematics
2 answers:
avanturin [10]3 years ago
7 0

Answer:

option B is the correct answer = TSA = 339.29 in²

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timurjin [86]3 years ago
3 0

Answer:339.29

Step-by-step explanation:

You might be interested in
Someone please help with these and explain your answer for both!!! I will give brainliest if correct!!!
goldenfox [79]

Answer:

C

Step-by-step explanation:

We have congruent angles in the middle and 2 sides are congruent as well which makes (Angle-Side-Side) which doesn't work for congruent triangles.

3 0
3 years ago
Read 2 more answers
(Hypothetical.) Suppose five measurements of the volume of a liquid yield the following data (in milliliters).
Digiron [165]

Answer:

The 95% confidence interval for the measurements is [48.106, 53.494].

Step-by-step explanation:

The average M of this sample is

M=\dfrac{1}{5}\sum_{i=1}^5x_i=\dfrac{1}{5}(52+48+49+52+53)\\\\\\M=\dfrac{254}{5}=50.800

The standard deviation s of this sample is

s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^5(x_i-M)^2}

s=\sqrt{\dfrac{1}{4}\cdot [(52-50.8)^2+(48-50.8)^2+(49-50.8)^2+(52-50.8)^2+(53-50.8)^2]}

s=\sqrt{\dfrac{1}{4}\cdot [(1.44)+(7.84)+(3.24)+(1.44)+(4.84)]}=\sqrt{\dfrac{18.8}{4}}=\sqrt{4.7}\\\\\\s=2.168

The degrees of freedom are

df=n-1=5-1=4

Then, the critical value of t for a 95% CI and 4 degrees of freedom is t=2.776.

The margin of error of the CI is:

E=t\cdot s/\sqrt{n}=2.776\cdot 2.17/\sqrt{5}=6.024/2.236=2.694

Then, the lower and upper bounds of the CI are:

LL=50.800-2.694=48.106\\\\UL=50.800+2.694=53.494

The 95% confidence interval for the measurements is [48.106, 53.494].

4 0
4 years ago
A 75% increase followed by a 33 1/2% decrease​
o-na [289]

After 75% increase followed by a 33 1/2% decrease the net increased is 16.375%.

<u>Solution:</u>

Need to determine net percentage increase or decrease when a value is increased by 75% and then decreased by 33 \frac{1}{2} \% that is 33.5%.

Let’s assume initial value be represented by variable x.

75 \% \text { decrease means } x+75 \% \text { of } x=x+\frac{75}{100} x=x+0.75 x=1.75 x

Now there is decrease of 33.5%

\begin{array}{l}{33.5 \% \text { decrease means } 1.75 x-33.5 \% \text { of } 1.75 x=1.75 x-\frac{33.5}{100} \times 1.75 x} \\\\ {=1.75 x-(0.335 \times 1.75) x=1.75 x-0.58625 x} \\\\ {=1.16375 x}\end{array}

\text { So increase in percentage }=\frac{\text { final value-initial value}}{\text { intial value }}

=\frac{1.16375 x-x}{x} \times 100=16.375 \%

Hence after 75% increase followed by a 33 \frac{1}{2} \% decrease the net increased is 16.375%.

8 0
3 years ago
Anybody know this!? Help please ..
lubasha [3.4K]
The slopes of perpendicular lines are negative reciprocal to each other
ex. the negative reciprocal to 5/2 is -2/5

once you find the perpendicular slope, you plug in the point and slope into the point-slope form of a line and then rearrange it into the slope-intercept form to get your answer

point slope
y-y_1 = m(x-x_1)

slope intercept form
y=mx+b
4 0
3 years ago
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
iren [92.7K]

Answer:

x = 14

y = 30

Step-by-step explanation:

x + 10 = 3x - 18

x = 3x - 18 - 10

x = 3x -28

x - 3x = -28

-2x = -28

x = 14

(3x - 18) + (6y - x - 10) = 180

3x - x -18 - 10 + 6y = 180

2x - 28 + 6y = 180

2x + 6y = 180 + 28

2(14) + 6y = 208

6y = 208 - 28

6y = 180

y = 30

I hope this helps!

5 0
3 years ago
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