Answer:
a) 0.19
b) 0.9689
c) ≈ 6 cars
Step-by-step explanation:
Rate at which cars arrive = 12 cars/hour = 1/5 cars/minute
time needed by each car to complete ATM transaction = 6 minutes = 1/6 car/minute
capacity of lane = 10 car
n = 10
<u>a) Calculate the probability of an arriving not using the ATM because the line is full</u>
p ( not using the ATM ) = 0.19
<u>b) probability that a car will not be able to use the ATM machine immediately on arrival</u>
P ( n > 0 ) = 1 - Po
= 1 - 0.0311 = 0.9689
<u>c) Average number of cars in the lane </u>
Lq = 5.74 ≈ 6 cars
attached below is the detailed solution
Answer:
181
Step-by-step explanation:
First, you need to find the value for g(10), that means that you have to substitute 10 in every x of g(x).
g(x)=x^2-10
g(10)=(10)^2-10
g(10)=100 - 10
g(10)= 90
Now that we have the value of g(10), we have to substitute in every x of f(x)
f(x)=2x+1
f(90) = 2(90) +1
f(90) = 180 +1
f(90) = 181
So the value of f[g(10)] is 181
Answer:
Step-by-step explanation:
I hope I helped you^_^
Answer:
9112.5
Step-by-step explanation:
36,450 divided by 4.