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anygoal [31]
4 years ago
10

Brett has a $30 online gift voucher. He plans to buy as many books as he can. The cost of each book is s4. There is also a singl

e shipping charge of $2. How many books can he afford without spending more than his gift voucher amount?
Mathematics
2 answers:
murzikaleks [220]4 years ago
4 0
Well, 4 times 7 is 28 and then plus 2 is 30! Therefore, he buy at the most 7 books.
Dima020 [189]4 years ago
4 0

General Idea:

When we are working with word problems, we need to follow the below steps:

<u>Step 1:</u> Assign variable for the unknown that we need to find.

<u>Step 2:</u> Write a meaningful mathematical equation using the sentence given

<u>Step 3:</u> Solve the equation by Performing reverse operation by Undoing whatever is done to the variable. Solving means find the value of the variable which will make the equation TRUE.

Applying the concept:

Step 1: Let x be the number of books that Brett can afford without spending more than his gift voucher amount.

Step 2: Writing mathematical equation based on the given sentence "Brett has a $30 online gift voucher. He plans to buy as many books as he can. The cost of each book is $4. There is also a single shipping charge of $2"

Online \; Gift \; Voucher=Number \; of  \; books  \; \times  \; Cost\;per \; Book \; + \; Single \; shipping \; charge

30=4x+2

Step 3: Solving equation

4x+2=30\\ Subtract \; 2 \; on \; both \; sides\\ \\ 4x+2-2=30-2\\ Combine \; like \; terms\\ \\ 4x=28\\ Divide  \; 4 \; on \; both \; sides\\ \\ \frac{4x}{4}= \frac{28}{4} \\ Simplifying  \; fraction \; on \; both \; sides\\ \\ x=7

Conclusion:

The number of books that Brett can afford without spending more than his gift voucher amount is <u>7</u> !!


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The planets in our solar system do not travel in circular paths. Rather, their orbits are elliptical. The Sun is located at a fo
qwelly [4]

1. The distance between the perihelion and the aphelion is 116 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Step-by-step explanation:

Let us revise the equation of the ellipse is

\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1 , where the major axis is parallel to the x-axis

  • The length of the major axis is 2a
  • The coordinates of the vertices are (± a , 0)
  • The coordinates of the foci are (± c , 0) , where c² = a² - b²

∵ The Sun is located at a focus of the ellipse

∴ The sun located ate c

∵ The perihelion is the point in a planet’s orbit that is closest to the

   Sun ( it is the endpoint of the major axis that is closest to the Sun )

∴ The perihelion is located at the vertex (a , 0)

∵ The closest Mercury comes to the Sun is about 46 million miles

∴ The distance between a and c is 46 million miles

∵ The aphelion is the point in the planet’s orbit that is furthest from

   the Sun ( it is the endpoint of the major axis that is furthest from

   the Sun )

∴ The aphelion is located at the vertex (-a , 0)

∵ The farthest Mercury travels from the Sun is about 70 million miles

∴ The distance from -a to c is 70 million miles

∴ The distance between the perihelion and the aphelion =

   70 + 46 = 116 million miles

1. The distance between the perihelion and the aphelion is 116 million miles

∵ The distance between the perihelion and the aphelion is the

  length of the major axis of the ellipse

∵ The length of the major axis is 2 a

∴ 2 a = 116

- Divide both sides by 2

∴ a = 58

∴ The distance from the center of Mercury’s elliptical orbit to the

   closest end point to the sun is 58 million miles

∵ The distance between the sun and the closest endpoint is

   46 million miles

∴ The distance from the center of Mercury’s elliptical orbit and

   the Sun = 58 - 46 = 12 million miles

2. The distance from the center of Mercury’s elliptical orbit and the Sun is 12 million miles

∵ The major axis runs horizontally

∴ The equation is \frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1

∵ a = 58

∵ c is the distance from the center to the focus of the ellipse

∴ c = 12

∵ c² = a² - b²

∴ (12)² = (58)² - b²

- Add b² to both sides

∴ (12)² + b² = (58)²

- Subtract (12)² from both sides

∴ b² = (58)² - (12)² = 3220

- Substitute these values in the equation

∴ \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

3. The equation of the elliptical orbit of Mercury is \frac{x^{2}}{3364}}+\frac{y^{2}}{3220}=1

The eccentricity (e) of an ellipse is the ratio of the distance from the

center to the foci (c) and the distance from the center to the

vertices (a) ⇒ e=\frac{c}{a}

∵ c = 12

∵ a = 58

∴ e=\frac{12}{58} = 0.207

4. The eccentricity of the ellipse is 0.207 to the nearest thousandth

If the eccentricity is zero, it is not squashed at all and so remains a circle.

If it is 1, it is completely squashed and looks like a line

∵ The eccentricity of the ellipse is 0.207

∵ This number is closed to zero than 1

∴ The shape of the ellipse is near to the shape of the circle

5. The value of the eccentricity tell you that the shape of the ellipse is near to the shape of the circle

Learn more:

You can learn more about conics section in brainly.com/question/4054269

#LearnwithBrainly

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Quick timer
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Answer is

geometric series
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A pattern calls for 2 1 over 4 yards of material and 1 1 over 4 yards of lining. How much total fabric is needed
Arada [10]
2 1/4+1 1/4=3 1/2
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Match the story with an equation.
Basile [38]

Answer:

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(8' - 0.25')/4=P

Step-by-step explanation:

P=length of each of the 4 pieces

(8' - 0.25')/4=P

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Help me please i need this now
ICE Princess25 [194]

Answer:

210?

Step-by-step explanation:

Sorry if it's wrong

4 0
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