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3 years ago

Can the degree of a monomial ever be a negative? please explain why or why not.

1 answer:

3 0

Greetings!

Yes, the degree on a monomial can be negative:

Example:
$9x^{-2}$

This is equal to:
$1/9x^{2}$

Hope this helps.
-Benjamin

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6 ten thousand 5 hundred x10

castortr0y [4]

Answer:

60,500

Step-by-step explanation:

6 0

4 years ago

Find the height of a cylinder with a volume of 12157 mm3 and a radius of 9 mm.

Ivahew [28]

Volume of a Cylinder = pi * r^2 * h

V / (pi*r^2) = h

12157 / (pi * 9^2) = h = 47.774

5 0

3 years ago

Monica works at a local bike shop. On Friday, she sold 5 mountain bikes and 10 road bikes. On Saturday, she sold 9 mountain bike

Delvig [45]

Answer:

they aren't the same ratio

Step-by-step explanation:

ratio of 5:10 then 9:15

5/10 and 9/15

and that is simplified

2.5/5 and 3/5 so they aren't the same ratio

5 0

3 years ago

8. A megaphone is formed by taking a cone with radius of 18 centimeters and an edge length of 60 centimeters from tip to base

kodGreya [7K]

The Surface area of the whole cone is 4408.56 cm²

The Surface area of the tips that is removed is 376.8 cm²

The Surface area of the megaphone(hollow) is 2712.96 cm²

<h3 /><h3>What is surface area?</h3>

Surface area is the sum of the areas of all faces (or surfaces) on a 3D shape.

Therefore,

Surface area of the whole cone = πr² + πrl

Therefore,

Surface area of the whole cone = πr(r + l)

where

r = radius = 18 cm
l = edge length = 60 cm

Surface area of the whole cone = 3.14 × 18(18 + 60) = 4408.56 cm²

Surface area of the tips that is removed = 3.14 × 4 (18 + 12) = 376.8 cm²

Surface area of the megaphone(hollow) = πrl

Surface area of the megaphone(hollow) = 3.14 × 18 × (60 - 12) = 2712.96 cm²

learn more on surface area here: brainly.com/question/7410402

4 0

2 years ago

3. Two cars are parked, 150m apart, and on opposite sides of a building. A camera on the top of the building rotates and can vie

allsm [11]

Answer:

<em>The building is 61.5 m tall</em>

Step-by-step explanation:

The image below is a diagram where all the given distances and angles are shown. We have additionally added some variables:

h = height of the building

a, b = internal angles of each triangle

x = base of each triangle

The angles a and b can be easily found by subtracting the given angles from 90° since they are complementary angles, thus:

a = 90° - 37° = 53°

b = 90° - 42° = 48°

Now we apply the tangent ratio on both triangles separately:

$\displaystyle \tan a=\frac{\text{opposite leg}}{\text{adjacent leg}}$

$\displaystyle \tan 53^\circ=\frac{150-x}{h}$

$\displaystyle \tan 48^\circ=\frac{x}{h}$

From the last equation:

$x=h.\tan 48^\circ$

Substituting into the first equation:

$\displaystyle \tan 53^\circ=\frac{150-h.\tan 48^\circ}{h}$

Operating on the right side:

$\displaystyle \tan 53^\circ=\frac{150}{h}-\tan 48^\circ$

Rearranging:

$\displaystyle \tan 53^\circ+\tan 48^\circ=\frac{150}{h}$

Solving for h:

$\displaystyle h=\frac{150}{\tan 53^\circ+\tan 48^\circ}$

Calculating:

h = 61.5 m

The building is 61.5 m tall

5 0

3 years ago