Help please will give brainliest answer
1 answer:
The first thing we must do for this case is to define variables.
We have then:
x: weight of the big box
y: weight of the small box.
We now write the system of equations that models the problem:
We apply the graphic solution.
For this, the solution will be the cut point of both lines.
We have then that the solution occurs for the point:
Note: see attached image
Answer:
Weight of each large box: 15.5 Kilograms
Weight of each small box: 13.25 Kilograms
We have then:
x: weight of the big box
y: weight of the small box.
We now write the system of equations that models the problem:
We apply the graphic solution.
For this, the solution will be the cut point of both lines.
We have then that the solution occurs for the point:
Note: see attached image
Answer:
Weight of each large box: 15.5 Kilograms
Weight of each small box: 13.25 Kilograms
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Answer:
Center = ( 1,-2)
radius = 2
Answer:
The graph is uploaded in the attachment.
The value of x is 2.625.
Step-by-step explanation:
- let us plot f(x), g(x) on y-axis
so, f(x)=y and g(x)=y.
- the first equation can be written as y=5-2x
- the general equation of a straight is y=mx+c
( where m is the slope and c is the y-intercept )
- now comparing given equation with the general equation mentioned above, the slope of first line is -2 and its y-intercept is 5
- the slope of second equation i.e, y=(2/3)x-2 is 2/3 and its y-intercept is -2.
- now plot the graph using above information.
(y-intercept is the the coordinate of a point where the line intersects y-axis)
(slope is the angle made by the line with the x-axis)
- by seeing the graph, the value of x is 2.625.
