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grandymaker [24]
3 years ago
10

Help please will give brainliest answer

Mathematics
1 answer:
Furkat [3]3 years ago
3 0
The first thing we must do for this case is to define variables.
 We have then:
 x: weight of the big box
 y: weight of the small box.
 We now write the system of equations that models the problem:
 8x + 4y = 177

3x + 2y = 73
 We apply the graphic solution.
 For this, the solution will be the cut point of both lines.
 We have then that the solution occurs for the point:
 (x, y) = (15.5, 13.25)

 Note: see attached image
 Answer:
 
Weight of each large box: 15.5 Kilograms
 
Weight of each small box: 13.25 Kilograms

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If m∠UNR = 180° find m∠RNS<br> A. 27°<br> B. 34°<br> C. 59°<br> D. 94°
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Answer:

Option A) m∠RNS=27°

Step-by-step explanation:

We know that m∠UNR = 180°. This tells us that the Sum of the enclosed angles should equal 180°, by trigonometry. So the enclosed angles are:

m∠RNS = (3x+6)^{o}

m∠SNT= (13x+3)^{o}

m∠TNU= (10x-11)^{o}

Now let us add all the angles and solve for the value of x as follow:

m_{RSN}+m_{SNT}+m_{TNU}=m_{UNR}\\\\(3x+6)+(13x+3)+(10x-11)=180\\\\3x+13x+10x+6+3-11=180\\\\26x-2=180\\\\26x=180+2\\\\26x=182\\\\

x=\frac{182}{26} \\\\x=7

Now lets plug in the value into the expression for angle m∠RNS to find the angle as:

RNS = (3x+6)^{o}\\\\RNS=(3(7)+6)^{o}\\\\RNS=(21+6)^{o}\\\\RNS=27^{o}

Thus Option A. is the correct answer.

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