On the coordinate plane, what quadrant is the point (1 , 4) located in?
2 answers:
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Answer:
CD ≠ EF
Step-by-step explanation:
Using the distance formula
d =
with (x₁, y₁ ) = C(- 2, 5) and (x₂, y₂ ) = D(- 1, 1)
CD =
=
= =
Repeat using (x₁, y₁ ) = E(- 4, - 3) and (x₂, y₂ ) = F(- 1, - 1)
EF =
=
= =
Since ≈
, then CD and EF are not congruent