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Assoli18 [71]
3 years ago
10

What does the graph of p(x)=5/2(4^x) look like?

Mathematics
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answe

Go to desmos online

Step-by-step explanation:

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What is the equivalent of 6/18​
bearhunter [10]

Answer:

1/3

Step-by-step explanation:

hope this helps :D

brainliest pls?

3 0
3 years ago
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Please help this is the only other question, Quarantine be killing me (thank god this is due till 10:30
Semenov [28]

Answer:

24m

Step-by-step explanation:

Area of a triangle = bh/2.

The base of this triangle is 6. The altitude for the bottom base is 8. Thus, 8 * 6 all over 2 is 24.

5 0
3 years ago
I am have trouble with these x-intercepts. Please help me.​
kotegsom [21]

Answer:

  1. x=8, x=2
  2. no solution
  3. no solution

Step-by-step explanation:

For the equation ...

  y = a(x -h)² +k

you can find the x-intercepts by setting y=0 and solving for x.

  0 = a(x -h)² +k

  -k = a(x -h)² . . . . . . subtract k

  -k/a = (x -h)² . . . . . divide by a

  ±√(-k/a) = x -h . . . . take the square root

  h ± √(-k/a) = x . . . . add h . . . . this is the general solution

__

So, for each of your problems, fill in the corresponding numbers and do the arithmetic. If (-k/a) is a negative number, the square root gives imaginary values, so there is "no solution".

1.  x = 5 ± √9 = {5 -3, 5 +3} = {2, 8} . . . . the x-intercepts are 2 and 8

2.  x = -3 ± √(-2) . . . . . . no solution; the roots are complex

3.  x = 5 ± √(-8/4) . . . . . no solution; the roots are complex

7 0
3 years ago
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A certain circle can be represented by the following equation. x^2+y^2+6y-72=0 What is the center of this circle ?
jek_recluse [69]

Answer:

(0, -3)

Step-by-step explanation:

Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."

Rearranging x^2+y^2+6y-72=0, we get  x^2 + y^2 + 6y                = 72.

x^2 is already a perfect square.  Focus on rewriting y^2 + 6y as the square of a binomial:  y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:

x^2 + y^2 + 6y + 9  - 9              = 72:

x^2 + (y + 3)^2 = 81

Comparing this to the standard equation of a circle with center at (h, k) and radius r,

(x - h)^2 + (y - k)^2 = r^2.  Then h = 0, k = -3 and r = 9.

The center of the circle is (h, k), or (0, -3).

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3 years ago
15 points!!! Find the volumes of these three figures
Dafna11 [192]

Answer:

Its only 6 points...

Step-by-step explanation:

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