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3 years ago

Which of these statements about algebra are true?

Mathematics

2 answers:

9966 [12]3 years ago

8 0

Answer:

Algebra uses abstract symbols to represent concrete elements in the real world.
Many great mathematicians were also philosophers.
The same variable can represent two different unknowns in two different algebraic expressions.

Step-by-step explanation:

Novay_Z [31]3 years ago

6 0

Yes, algebra uses abstract symbols to represent concrete elements in the real world.

No, in an algebraic equation, the same variable cannot represent two different unknowns.

Yes, many great mathematicians were also philosophers.

No, An algebraic expression doesn't contains an equal sign, but an algebraic equation does.

No, if the expressions are in the same set. Yes, if they are not. (The same variable can represent two different unknowns in two different algebraic expressions.)

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A data set of 5 observations for Concession Sales per person at a theater and Minutes before the movie begins results in the est

otez555 [7]

Answer:

Check the explanation

Step-by-step explanation:

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5 0

2 years ago

Simplify (5x−2+3x^2)+(4x+3)

Art [367]

Answer:

3x^2 + 9x + 1

3x ( x + 3 ) + 1

Step-by-step explanation:

(5x - 2 +3x^2 ) + (4x + 3 )

To make this a little bit more easier to read, you can remove the parentheses:

5x - 2 + 3x^2 + 4x + 3

Now, write in a way so that the like terms are next to each other:

3x^2 + 5x + 4x - 2 + 3

Now simplify the 'x' terms to get:

3x^2 + 9x - 2 + 3

Now, simplify the integers (the ones with now variables with them) to get:

3x^2 + 9x + 1

If you want, you can factor out the 3x for two of the terms to get :

3x ( x + 3 ) + 1

Therefore, your simplest form can either be 3x^2 + 9x + 1 OR 3x (x + 3 ) + 1

5 0

3 years ago

Karin wants to use the distributive property to mentally find the value of 19⋅42+19⋅58. Which expression can she use?

devlian [24]

Answer:

$19( 42+ 58)$

Step-by-step explanation:

$19 \cdot 42+19 \cdot 58\\$

The common factor is 19

$19( 42+ 58)$

3 0

3 years ago

Read 2 more answers

I need help on these problems

VikaD [51]

Someone is writing the answer so ill just give you this tip for whenever.
A negitive times a negitive is positive
a negative times a positive is negitive
and a positive times a positive is positive (just had to add it to be complete)

8 0

2 years ago

The annual energy consumption of the town where Camilla lives in creases at a rate that is onal at any time to the energy consum

boyakko [2]

Answer:

6.575 trillion BTUs

Step-by-step explanation:

Let represent the annual energy consumption of the town as E

The rate of annual energy consumption * energy consumption at time past

dE/dt * E

dE/dt =K

k = the proportionality constant

c= the integration constant

(dE/dt=) kdt

lnE = kt + c

E(t) = e^kt+c ⇒ e^c e^kt e^c is a constant, and e^c = E₀

E(t) = E₀ e^kt

The initial consumption of energy is E(0)=4.4TBTU

set t = 0 then

4.4 = E₀ e⇒ E₀ (1)

E₀ = 4.4

E (t) = 4.4e^kt

The consumption after 5 years is t = 5, e(5) = 5.5TBTU

so,

E(5) = 5.5 = 4.4e^k(5)

e^5k = 5/4

We now take the log 5kln = ln(5/4)

5k(1) = ln(5/4)

k = 1/5 ln(5/4) = 0.04463

We find the town's annual energy consumption, after 9 years

we set t=9

E(9) = 4.4e^0.04463(9)

= 4.4(1.494301) = 6.5749TBTUs

Therefore the annual energy consumption of the town after 9 years is

= 6.575 trillion BTUs

3 0

3 years ago