Which of these statements about algebra are true?

Mathematics

2 answers:

9966 [12]3 years ago

8 0

Answer:

Algebra uses abstract symbols to represent concrete elements in the real world.
Many great mathematicians were also philosophers.
The same variable can represent two different unknowns in two different algebraic expressions.

Step-by-step explanation:

Novay_Z [31]3 years ago

6 0

Yes, algebra uses abstract symbols to represent concrete elements in the real world.

No, in an algebraic equation, the same variable cannot represent two different unknowns.

Yes, many great mathematicians were also philosophers.

No, An algebraic expression doesn't contains an equal sign, but an algebraic equation does.

No, if the expressions are in the same set. Yes, if they are not. (The same variable can represent two different unknowns in two different algebraic expressions.)

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(x+2)(x-18)=0<br><br>FIND THE SOLUTIONS OF THE EQUATION

vladimir2022 [97]

Either one at any given time could be equal to zero. So
x + 2 = 0
x = - 2

x - 18 = 0
x = 18

I've enclosed a graph of this so you can see that the answers I've given are the ones expected.

6 0

3 years ago

Read 2 more answers

What is (99/100)^101 times (100/99)^100?

sineoko [7]

Answer:

99/100

Step-by-step explanation:

First of all recall that

$a^n\cdot b^n =(ab)^n$

Now we we will try to apply that formula for $a=99/100$ and $b=100/99$ .

First rewrite $(99/100)^{101}=(99/100)\times (99/100)^{100}$

Now

$(99/100)\times (99/100)^{100}\times (100/99)^{100}\\=(99/100)\times ((99/100)\times (100/99))^{100}\\=(99/100)\times 1^{100}\\=(99/100)\times 1\\=99/100$