Choose 3 values for x that would make this inequality true. X - 4<20
1 answer:
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Answer: 60
Step-by-step explanation:
Let the side lengths of the rectangular pan be m and n. It follows that (m-2) (n-2)=
So, since haf of the brownie pieces are in the interior. This gives 2 (m-2) (n-2) =mn
mn- 2m - 2n- 4 = 0
Then Adding 8 to both sides and applying, we obtain (m-2) (n-2) =8
Since now, m and n are both positive, we obtain (m,n) = (5,12), (6,8) (up to ordering). By inspection, 5. 12 = 60
which maximizes the number of brownies in total which is the greatest number.
Hope that helped! =)
This is how the first one would be done. sorry if it’s a little messy the answer is 9. but try using photomath for the rest. it gives you the answer and explains how to do it
