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Sedbober [7]
3 years ago
7

Describe in words how you would solve the linear system y = 3x + 1 and y = - 2x + 3.

Mathematics
1 answer:
Sergio [31]3 years ago
5 0
We are using substitution to solve this problem.

y=3x+1
y=-2x+3
Make these equal each other: 3x+1=-2x+3
Add 2x to both sides: 3x+2x+1=-2x+2x+3
= 5x+1=3
Subtract 1 from both sides; 5x+1-1=3-1
= 5x=2
Divide 5 from both sides: 5x/5=2/5
X= 2/5
Plug X into one of the equations: y=3(2/5) +1
y=11/5(2.2)

(2/5,11/5)
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Find the equation of the line that passes through points (3,5) and (-6,2). Write the equation in slope intercept form.
andrezito [222]
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                              = ¹/₃
   
     using the point-slope form (y-y₁) = m(x-x₁)
     using (3,5)
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        ⇒      <span>  y =   ¹/₃ x  + 4  [OPTION D]


</span>2)        y =  2x  +  5  .... (1)
<span>           </span>y = ¹/₂ x  + 6  .... (2)
       
         by substituting y in (1) for y in (2)

           2x  +  5 = ¹/₂ x  + 6 
                 ³/₂ x = 1
                      x = ²/₃

        by substituting found x (2)

            y = ¹/₂ (²/₃)  + 6
            y = ¹⁹/₃

∴ common point is (²/₃ , ¹⁹/₃)  thus answer is FALSE [OPTION B]


3) Yes [OPTION A]
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4) No [OPTION B]
       Two lines are perpendicular if their gradients multiply to give - 1 and as such one is the negative reciprocal of the other.  Since both gradients are ¹/₂ then they are actually parallel and not perpendicular.

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Step-by-step explanation:

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