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3 years ago

Describe in words how you would solve the linear system y = 3x + 1 and y = - 2x + 3.

1 answer:

5 0

We are using substitution to solve this problem.

y=3x+1
y=-2x+3
Make these equal each other: 3x+1=-2x+3
Add 2x to both sides: 3x+2x+1=-2x+2x+3
= 5x+1=3
Subtract 1 from both sides; 5x+1-1=3-1
= 5x=2
Divide 5 from both sides: 5x/5=2/5
X= 2/5
Plug X into one of the equations: y=3(2/5) +1
y=11/5(2.2)

(2/5,11/5)

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Answer:

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Step-by-step explanation:

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3.) Simplify the expression.

Bogdan [553]

Answer:

Option C) -cosu is correct

Therefore the simplified expression is $cos(u+\pi)=-cosu$

Step-by-step explanation:

Given expression is $cos(u+\pi)$

To find the value of the given expression :

By using the formula $cos(A+B)=cosAcosB-sinAsinB$

Substitute A=u and $B=\pi$ in the above formula we get

$cos(u+\pi)=cosucos\pi-sinusin\pi$

$=cosu(-1)-sinu(0)$ ( here $cos\pi=-1$ and $sin\pi=0$ )

$=-cosu-0$

$=-cosu$

$cos(u+\pi)=-cosu$

Therefore option C) -cosu is correct

Therefore the simplified expression is $cos(u+\pi)=-cosu$

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3 years ago

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Answer: Multiplication

Step-by-step explanation:

Given

w/7=14

Multiply 7 on both sides

w/7 × 7=14 × 7

w=98

In order to isolate w on one side, we should times 7 as the numerator in order to eliminate the 7 in the denominator. To promise equality, we need to multiply 7 on both sides in order to isolate w and solve the equation.

<h2>Thus, it is multiplication.</h2>

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