3 years ago

How do I write an equation in standard form for a line that passes through (2,2) and (0,-3)

1 answer:

sweet [91]3 years ago

5 0

It is the first one!!

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skad [1K]

Forty three million, eighty thousand seven hundred

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3 years ago

r-ruslan [8.4K]

<span>87 degrees
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3 years ago

nasty-shy [4]

Answer:

Standard form of $(x-9)(3x-7) + (3x^{2} - 5x+2)$ $=6x^{2} - 39x + 65$

Step-by-step explanation:

Here, the given expression is $(x-9)(3x-7) + (3x^{2} - 5x+2)$

Now, simplifying the above expression in parts, we get

$(x-9)(3x-7) = 3x^{2} - 7x -27x + 63 = 3x^{2} - 34x + 63$

hence, combining both parts:

$(x-9)(3x-7) + (3x^{2} - 5x+2)$ $=(3x^{2} -34x +63) + (3x^{2} - 5x+2)$

= $6x^{2} - 39x + 65$

The above expression is of the STANDARD FORM: $ax^{2} +bx + c$

Hence, the standard form of $(x-9)(3x-7) + (3x^{2} - 5x+2)$ $=6x^{2} - 39x + 65$

6 0

3 years ago

Svetlanka [38]

First part its 4C2 = 4*3 / 2 = 6

Second part
12 * 100
---------- = 4.3 %
280

3 0

3 years ago

ratelena [41]

Answer:

f/6=17

f=17×6

=102

Hope it helps!!!

7 0

2 years ago