The answer to the problem is 60.
To solve this problem,lets say that
X = the weight of the machine components. <span>
<span>X is normally distributed with mean=8.5 and sd=0.09
We need to find x1 and x2 such that
P(X<x1)=0.03 and P(X>x2)=0.03
<span>Standardizing:
<span>P( Z< (x1 - 8.5)/0.09 ) =0.03
P(Z > (x2 - 8.5)/0.09 ) =0.03.
<span>From the Z standard table, we can see that approximately P
= 0.03 is achieved when Z equals to:</span></span></span></span></span>
<span>z = -1.88 and z= 1.88</span>
Therefore,
P(Z<-1.88)=0.03 and P(Z>1.88)=0.03 <span>
So,
(x1 - 8.5)/0.09 = -1.88 and
(x2 - 8.5)/0.09 =1.88
Solving for x1 and x2:
<span>x1=-1.88(0.09) + 8.5 and
<span>x2=1.88(0.09) + 8.5
<span>Which yields:
<span><span>x1 = 8.33 g</span>
<span>x2 = 8.67 g</span></span></span></span></span></span>
<span>Answer: The bottom 3 is separated by the weight
8.33 g and the top 3 by the weight 8.67 g.</span>
Answer:
is there a picture to go with the problem?
The answer is 6
Explanation: 7.50•6+2=44 and 6•6+8=44
