All categories

3 years ago

What is the GCF of 48m5n and 81m2n2?

2 answers:

7 0

To find the GCF of the two terms, continuous division must be done.
What can be used to divide both terms such that there is not a remainder?
Start small, let's take 2. It could be a GCF.
Move up higher, say 3. Yes, it can be a GCF.
To see if there might be a greater common factor, divide the constants by 3.
48/3 = 16
81/3 = 27
Upon inspection and contemplation, there is no more common factor between 16 and 27. So, 3 is the GCF.

Moving on, when it comes to variables. The variable with the least exponents is easily the GCF. For the variable m, the GCF is m2 and for n, the GCF is n.

Combining the three, we have the overall GCF = 3m2n

padilas [110]3 years ago

6 0

Answer: 3m2n

Fuh online skool‍♂️

You might be interested in

Answer fast really need help. Thank you. I will give brainliest.

Vlad1618 [11]

Answer:

Search it

Step-by-step explanation:

Search it up

5 0

3 years ago

Lucas and his sister Luisa are saving to buy a birthday present for their mother. The present costs $95. Lucas earns $16 per wee

madreJ [45]

Your answer should be c

6 0

3 years ago

The length and width of a rectangular room are measured to be 3.955±0.005m. Calculate the area of the room and its uncertainty i

Margarita [4]

Answer:

The area of the room and its uncertainty in square meters is:

15.642±0.040 $m^2$

Step-by-step explanation:

We know the area of a rectangular room is the multiplication of the length and width:

$Area= 3.955m*3.955m\\Area= 15.642 m^2$

Now we need to know the uncertainty, the uncertainty of a multiplication is:

$\frac{δ_a}{|Area|} =\frac{δ_L}{|L|}+\frac{δ_W}{|W|}$ (1)

$δ_A$ : Area uncertainty

$δ_L$ : Length uncertainty

$δ_W$ : Width uncertainty

A: Area of the room

L: Length

W: Width

Clearing the uncertainty of the area:

$δ_A=(\frac{δ_x}{|x|}+\frac{δ_y}{|y|})*Area$ (2)

$δ_A=(\frac{0.005}{|3.955|}+\frac{0.005}{|3.955|})*15.642 m^2$

$δ_A= 0.040 m^2$

The area of the room and its uncertainty in square meters is:

15.642±0.040 $m^2$

6 0

3 years ago

There are some Nichols dimes and quarters in a large piggy bank for every two nickels there a sweetheart forever to Diane’s ther

grigory [225]

Answer:

There are 80 nickels, 120 dimes and 300 quarters in the piggy bank.

All coins in the piggy bank worth $91.

Step-by-step explanation:

Please consider the complete question:

There are some nickels, dimes, and quarters in a large piggy bank. For every 2 nickels there are 3 dimes. For every 2 dimes there are 5 quarters. There are 500 coins total. How many nickels, dimes, and quarters are in the piggy bank? Explain your reasoning. How much are the coins in the piggy bank worth?

Let n, d, q represent number of nickles, dimes and quarters respectively.

For every 2 nickels there are 3 dimes. We can represent this information in an equation as:

$\frac{2}{n}=\frac{3}{d}...(1)$ or