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galben [10]
2 years ago
9

What is 1/3 of 30% of 5/6 of 0.6 of 12?

Mathematics
1 answer:
aliina [53]2 years ago
8 0

Step-by-step explanation:

\frac{1}{3 } \times  \frac{30}{1}  = 10 \\  \\  \frac{10}{1}  \times  \frac{5}{6}  = 8.33 \\  \\  \frac{833}{100}  \times  \frac{6}{10}  = 4.998 \\  \\  \frac{4998}{1000}  \times  \frac{12}{1}  = 59.976

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If X=60, Y=25, and Z=65, what is the tangent of
LekaFEV [45]
Tangent is opposite/adjacent so it would 60/25 which simplifies to 12/5
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3 years ago
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A small cube with side length 6y is placed inside a larger cube with side length 4x^2. What is the difference in the volume of t
olasank [31]

Answer:

64x⁶ - 216y³

Step-by-step explanation:

The formula for the volume of a cube is  

Vol. = l³

For the large cube,  

V =(4x²)³

V = 64x⁶

For the small cube,  

v =(6y)³

v = 216y³

The difference in volume is

Diff. = 64x⁶ - 216y³

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3 years ago
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scZoUnD [109]
Measure the lengths of the runways in inches and then times your answer by 700 and then round that answer.

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3 years ago
A village lost 15% of its cows in a flood and 10% of the remainder died of
Free_Kalibri [48]

Answer:

10000 cows.

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7 0
3 years ago
A company with a large fleet of cars wants to study the gasoline usage. They check the gasoline usage for 50 company trips chose
Nookie1986 [14]

Answer:

The 95% confidence interval is given by (25.71536 ;28.32464)

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)  

Step-by-step explanation:

Notation and definitions  

n=50 represent the sample size  

\bar X= 27.2 represent the sample mean  

s=5.83 represent the sample standard deviation  

m represent the margin of error  

Confidence =88% or 0.88

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

Calculate the critical value tc  

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 88% of confidence, our significance level would be given by \alpha=1-0.88=0.12 and \alpha/2 =0.06. The degrees of freedom are given by:  

df=n-1=50-1=49  

We can find the critical values in R using the following formulas:  

qt(0.06,49)

[1] -1.582366

qt(1-0.06,49)

[1] 1.582366

The critical value tc=\pm 1.582366  

Calculate the margin of error (m)  

The margin of error for the sample mean is given by this formula:  

m=t_c \frac{s}{\sqrt{n}}  

m=1.582366 \frac{5.83}{\sqrt{50}}=14.613  

With R we can do this:

m=1.582366*(5.83/sqrt(50))

m

[1] 1.304639

Calculate the confidence interval  

The interval for the mean is given by this formula:  

\bar X \pm t_{c} \frac{s}{\sqrt{n}}  

And calculating the limits we got:  

27.02 - 1.582366 \frac{5.83}{\sqrt{50}}=25.715  

27.02 + 1.582366 \frac{5.83}{\sqrt{50}}=28.325

Using R the code is:

lower=27.02-m;lower

[1] 25.71536

upper=27.02+m;upper

[1] 28.32464

The 95% confidence interval is given by (25.71536 ;28.32464)  

And if we need to round we can use the following excel code:

round(lower,2)

[1] 25.72

round(upper,2)

[1] 28.32

And the interval would be (25.72; 28.32)  

6 0
3 years ago
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